The kinetic energy of a motorcycle and driver is 65,662 J. If their total mass is 500 kg, what is their velocity (in m/s)? Your Answer:

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

The kinetic energy of a motorcycle and driver is 65,662 J. If their total mass is 500 kg, what is their velocity (in m/s)?

**Your Answer:** 

---

**Explanation:**

To solve this problem, we use the formula for kinetic energy:

\[ KE = \frac{1}{2}mv^2 \]

where \( KE \) is the kinetic energy, \( m \) is the mass, and \( v \) is the velocity.

Given:

- \( KE = 65,662 \, \text{J} \)
- \( m = 500 \, \text{kg} \)

You need to solve for \( v \):

\[ 65,662 = \frac{1}{2} \times 500 \times v^2 \]

Solve for \( v \):

1. Multiply both sides by 2:

\[ 131,324 = 500 \times v^2 \]

2. Divide both sides by 500:

\[ v^2 = 262.648 \]

3. Take the square root of both sides:

\[ v = \sqrt{262.648} \]

Calculate the value of \( v \) to find the velocity in meters per second.
Transcribed Image Text:**Problem Statement:** The kinetic energy of a motorcycle and driver is 65,662 J. If their total mass is 500 kg, what is their velocity (in m/s)? **Your Answer:** --- **Explanation:** To solve this problem, we use the formula for kinetic energy: \[ KE = \frac{1}{2}mv^2 \] where \( KE \) is the kinetic energy, \( m \) is the mass, and \( v \) is the velocity. Given: - \( KE = 65,662 \, \text{J} \) - \( m = 500 \, \text{kg} \) You need to solve for \( v \): \[ 65,662 = \frac{1}{2} \times 500 \times v^2 \] Solve for \( v \): 1. Multiply both sides by 2: \[ 131,324 = 500 \times v^2 \] 2. Divide both sides by 500: \[ v^2 = 262.648 \] 3. Take the square root of both sides: \[ v = \sqrt{262.648} \] Calculate the value of \( v \) to find the velocity in meters per second.
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