The K₂ of a monoprotic weak acid is 0.00493. What is the percent ionization of a 0.103 M solution of this acid? 21.9 percent ionization: Incorrect %

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Problem:** The \( K_a \) of a monoprotic weak acid is 0.00493. What is the percent ionization of a 0.103 M solution of this acid?

**Answer Box (Incorrect Submission):**
- **percent ionization:** 21.9 %

**Feedback:**
- **Status:** Incorrect 

When working on this problem, use the percent ionization formula for weak acids, which is:

\[ \text{Percent Ionization} = \left( \frac{[\text{H}^+]}{[\text{HA}]} \right) \times 100\]

Where:
- \( [\text{H}^+] \) is the concentration of hydrogen ions after ionization.
- \( [\text{HA}] \) is the initial concentration of the weak acid solution.
 
Further steps typically involve setting up an equilibrium expression involving \( K_a \) and solving for the concentration of ionized acid.
Transcribed Image Text:**Problem:** The \( K_a \) of a monoprotic weak acid is 0.00493. What is the percent ionization of a 0.103 M solution of this acid? **Answer Box (Incorrect Submission):** - **percent ionization:** 21.9 % **Feedback:** - **Status:** Incorrect When working on this problem, use the percent ionization formula for weak acids, which is: \[ \text{Percent Ionization} = \left( \frac{[\text{H}^+]}{[\text{HA}]} \right) \times 100\] Where: - \( [\text{H}^+] \) is the concentration of hydrogen ions after ionization. - \( [\text{HA}] \) is the initial concentration of the weak acid solution. Further steps typically involve setting up an equilibrium expression involving \( K_a \) and solving for the concentration of ionized acid.
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