The joint probability mass function of X and Y is given by p(1, 1) = 0.05 p(1,2) = 0.1 p(1, 3) = 0.05 p(2, 1) = 0.1 p(2, 2) = 0.25 p(2, 3) = 0.1 p(3, 1) = 0.05 p(3,2) = 0.1 p(3,3) = 0.2 (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = .2222 %3D P(Y = 2|X = 2) = .5556 P(Y = 3|X = 2) = .2222 (b) Are X and Y independent? (enter YES or NO) NO (c) Compute the following probabilities: P(X+Y > 3) = .65 P(XY = 3) = .1 P( > 2) = | .05
The joint probability mass function of X and Y is given by p(1, 1) = 0.05 p(1,2) = 0.1 p(1, 3) = 0.05 p(2, 1) = 0.1 p(2, 2) = 0.25 p(2, 3) = 0.1 p(3, 1) = 0.05 p(3,2) = 0.1 p(3,3) = 0.2 (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = .2222 %3D P(Y = 2|X = 2) = .5556 P(Y = 3|X = 2) = .2222 (b) Are X and Y independent? (enter YES or NO) NO (c) Compute the following probabilities: P(X+Y > 3) = .65 P(XY = 3) = .1 P( > 2) = | .05
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 9PPS
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![The joint probability mass function of X andY is given by
p(1, 1) = 0.05 p(1,2) = 0.1
p(1, 3) = 0.05
p(2, 1) = 0.1
p(2, 2) = 0.25 p(2,3) = 0.1
p(3, 1) = 0.05 p(3,2) = 0.1
p(3,3) = 0.2
(a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = .2222
P(Y = 2|X = 2) = .5556
P(Y = 3|X = 2) = .2222
(b) Are X andY independent? (enter YES or NO) NO
(c) Compute the following probabilities:
P(X+Y > 3) = .65
P(XY = 3) = .1
P( > 2) = .05](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fac014c0c-39ba-4db9-b5ce-0c9de6d6411a%2F11a63450-4f7e-40ba-acb7-fa75c0670002%2F5klsq2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The joint probability mass function of X andY is given by
p(1, 1) = 0.05 p(1,2) = 0.1
p(1, 3) = 0.05
p(2, 1) = 0.1
p(2, 2) = 0.25 p(2,3) = 0.1
p(3, 1) = 0.05 p(3,2) = 0.1
p(3,3) = 0.2
(a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = .2222
P(Y = 2|X = 2) = .5556
P(Y = 3|X = 2) = .2222
(b) Are X andY independent? (enter YES or NO) NO
(c) Compute the following probabilities:
P(X+Y > 3) = .65
P(XY = 3) = .1
P( > 2) = .05
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