The joint probability distribution of two random variables X, Y is given in the table below.Value of Y-4 -2 0 2-4 .09 .03.13 .05-3 .19 .11 .01 .02Value of X-2 .07 .03 .12 .00-1 .00 .15 .00 .00From the information in the table, calculate each of the following three probabilities.P (x = 0) = 0P (x = -3, Y > -2) = 0P(Y > 0) = 0

Here, Values of X are -1,-2,-3,-4. Values of Y are -4,-2,0,2. The joint probability distribution of…

Answered: The joint probability distribution of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The joint probability distribution of two random variables X, Y is given in the table below. Y=-3 Y=0 Y=1 X=-4 0.01 0.00 0.17 X=-3 0.21 0.19 0.02 X=4 0.22 0.05 0.13 From the information in the table, calculate each of the following three probabilities. (a) P(x 0) = [
Fill in the P(X=x) values to give a legitimate probability distribution for the discrete random variable X, whose possible values are −4, 2, 3, 5, and 6. ValuexofX P=Xx −4 0.28 2 3 0.11 5 0.28 6
Please calculate the expected values, E(X) and E(Y), for the two random variables.
The joint probability distribution of two random variables X, Y is given in the table below. Y=-3 Y=3 Y=4 X=-4 0.11 0.29 0.02 X=-1 0.01 0.00 0.25 X=3 0.13 0.00 0.19 From the information in the table, calculate each of the following three probabilities. (a) P(X 3) %3D ‑ (c) P(x= -4) =0
The discrete random variable X has the following probability distribution: -10 0 10 p(x) 0.20 0.40 .10 Which one of the following correctly gives the value of the mean and standard deviation of X? OH = 0.5, o = 37.5 OH = 2.25, o = 37.25 OH = 0.5, o = 6.10 OH= 2.25, o = 6.10 OH= 0.5 o = 37.25
The joint probability distribution of two random variables X, Y is given in the table below. Y=-3 Y=1 Y=2 X=-4 0.03 0.00 0.08 X=0 0.27 0.14 0.06 X=3 0.20 0.16 0.06 From the information in the table, calculate each of the following three probabilities. (a) P(X> -4) = [ (b) P(Y = 2) = [] (c) P(X > 0.Y < 1) = 1 Check Explanation ALEKS - Britney Fri.
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suppose that X is a random variable with probability distribution.P(X=k)= 0.02k,where k takes the values 8,12,10,20. find the mean of X.
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The random variable x is the number of houses sold by a realtor in a single month at the Sendsom's Real Estate office. Find the mean of the probability distribution. Houses Sold (x) Probability P(x) 0 0.24 1 0.01 2 0.12 3 0.16 4 0.01 5 0.14 6 0.11 7 0.21 μμ = 3.50 μμ = 3.35 μμ = 3.60 μμ = 3.40
The joint probability distribution of two random variables X, Y is given in the table below. Y=-3 Y=2 Y=4 X=-4 0.02 0.14 0.13 X=-2 0.05 0.01 0.05 X=-1 0.09 0.00 0.11 X=1 0.12 0.15 0.07 X= 3 0.06 0.00 0.00 From the information in the table, calculate each of the following three probabilities. (a) P(Y> 2) = [ (b) P(X < 1,Y = 2) = | (c) P(Y< -3) = [] I Don't Know Submit O 2022 to search ALEKS - Britney Fri.
Let X be a random variable with the following probability values. F(x)= c(1-2x2+x®), x= 0,1,2,3,4,5. (a) Find the value of c to make it a probability distribution. (b) Establish the probability distribution of X (table). (c) Find the mean of the random variable X.

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