The joint distribution function of X and Y random variables is given below: - e-0.5az) (0.5 – e-203) ,x > 0, y > 0, a > 0, B > 0, ,otherwise. F,(1, y) = {6 (2 Find the marginal function of X and Y random variables. a. (2 – e-Ba) ,x > 0, B > 0, , otherwise. F-(x) = F, (4) = {{ S (0.5 – e-20y) ,y > 0, a > 0, otherwise. F, (y) Ob. F- (x) = { (-e-05az) ,x > 0, a > 0, , otherwise. (0.5 – e-By) ,y > 0, B > 0, , otherwise. F,(1) = (2 – e-aay) , xy > 0, a > 0, , otherwise. | F,(x) = %3D S (0.5 – e-2Bry) F,(y) = {} , ry > 0, B > 0, , otherwise. %3D d. F, (x) = (0.5 — е аz) ,x > 0, a > 0, , otherwise. ,Y > 0, B > 0, , otherwise. S (2 – e-0.5py) F,(y) = (2 — е -0.5аz) O e. F.(x) = ,x > 0, a > 0, otherwise. S (0.5 – e-2By) , Y > 0, B > 0, otherwise. F,(y) =

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The joint distribution function of X and Y random variables is given below:

Find the marginal function of X and Y random variables.

The joint distribution function of X and Y random variables is given below:
- e-0.5az) (0.5 – e-203)
,x > 0, y > 0, a > 0, B > 0,
,otherwise.
F,(1, y) = {6
(2
Find the marginal function of X and Y random variables.
a.
(2 – e-Ba)
,x > 0, B > 0,
, otherwise.
F-(x) =
F, (4) = {{
S (0.5 – e-20y)
,y > 0, a > 0,
otherwise.
F, (y)
Ob.
F- (x) = { (-e-05az)
,x > 0, a > 0,
, otherwise.
(0.5 – e-By)
,y > 0, B > 0,
, otherwise.
F,(1) =
(2 – e-aay)
, xy > 0, a > 0,
, otherwise.
|
F,(x) =
%3D
S (0.5 – e-2Bry)
F,(y) = {}
, ry > 0, B > 0,
, otherwise.
%3D
d.
F, (x) =
(0.5 — е аz)
,x > 0, a > 0,
, otherwise.
,Y > 0, B > 0,
, otherwise.
S (2 – e-0.5py)
F,(y) =
(2 — е -0.5аz)
O e. F.(x) =
,x > 0, a > 0,
otherwise.
S (0.5 – e-2By)
, Y > 0, B > 0,
otherwise.
F,(y) =
Transcribed Image Text:The joint distribution function of X and Y random variables is given below: - e-0.5az) (0.5 – e-203) ,x > 0, y > 0, a > 0, B > 0, ,otherwise. F,(1, y) = {6 (2 Find the marginal function of X and Y random variables. a. (2 – e-Ba) ,x > 0, B > 0, , otherwise. F-(x) = F, (4) = {{ S (0.5 – e-20y) ,y > 0, a > 0, otherwise. F, (y) Ob. F- (x) = { (-e-05az) ,x > 0, a > 0, , otherwise. (0.5 – e-By) ,y > 0, B > 0, , otherwise. F,(1) = (2 – e-aay) , xy > 0, a > 0, , otherwise. | F,(x) = %3D S (0.5 – e-2Bry) F,(y) = {} , ry > 0, B > 0, , otherwise. %3D d. F, (x) = (0.5 — е аz) ,x > 0, a > 0, , otherwise. ,Y > 0, B > 0, , otherwise. S (2 – e-0.5py) F,(y) = (2 — е -0.5аz) O e. F.(x) = ,x > 0, a > 0, otherwise. S (0.5 – e-2By) , Y > 0, B > 0, otherwise. F,(y) =
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