The inverse z-transform ofe - 3ROC: e < z <3 is,a>oz-e*)(z-3)(a) (e)" u[n]– 3*u[r](b) -(e-)" u[-n-1]-3"u[n](c) -(e)"u[-n-1]-3"u[-n=1](d) (e-)" u[n] -3*u[-n-1]

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The inverse z-transform of ea - 3 ROC: e < z <3 is, -a>0 (z-e")(z-3) (a) (e)" u[n]–3"u[n] (b) -(e*)"«[-n-1]-3"u[n] (c) -(e)"u[-n-1]+ 3"u[=n=1] (d) (e-)" u[7] +3"z[-n-1]

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.10MCQ

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Question

The inverse z-transform of
e - 3
ROC: e < z <3 is,
a>o
z-e*)(z-3)
(a) (e)" u[n]– 3*u[r]
(b) -(e-)" u[-n-1]-3"u[n]
(c) -(e)"u[-n-1]-3"u[-n=1]
(d) (e-)" u[n] -3*u[-n-1]

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