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The inverse square law expresses the attenuation of intensity as sound moves away from its source: 4= (*)* Given that we measure a sound intensity level of 1.6 W/m² at 3.1 meters from a sound source in an open space, what would we expect the intensity to be at a distance of 53.1 meters? Please give your answer in mW/m² (1 W = 1 000 mW).

The inverse square law expresses the attenuation of intensity as sound moves away from its source: 4= (*)* Given that we measure a sound intensity level of 1.6 W/m² at 3.1 meters from a sound source in an open space, what would we expect the intensity to be at a distance of 53.1 meters? Please give your answer in mW/m² (1 W = 1 000 mW).

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How to find intensity at a distance of 53.1 meters? 

The inverse square law expresses the attenuation of intensity as sound moves away from its source: 4 = (4) ² Given that we measure a sound intensity level of 1.6 W/m² at 3.1 meters from a sound source in an open space, what would we expect the intensity to be at a distance of 53.1 meters? Please give your answer in mW/m² (1 W = 1 000 mW). (you may enter just your answer in mW/m², without any units)
Transcribed Image Text:The inverse square law expresses the attenuation of intensity as sound moves away from its source: 4 = (4) ² Given that we measure a sound intensity level of 1.6 W/m² at 3.1 meters from a sound source in an open space, what would we expect the intensity to be at a distance of 53.1 meters? Please give your answer in mW/m² (1 W = 1 000 mW). (you may enter just your answer in mW/m², without any units)
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