The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputs the inversed value. The code contains errors. Find and fix the errors. Ex: If the input is 0.500, then the output is: The inverse of current = 1 / 0.500 = 2.000 1 import java.util.Scanner; 2 3 public class CurrentInverse { 4 5 6 7 8 9 10 11 12 13 14 15 16 17 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); /* Modify the following code */ int current; int currentInverse; current scnr.nextInt (); currentInverse = 1 / current; System.out.printf("The inverse of current = 1 / %.3f", current); System.out.printf(" = %.3f\n", currentInverse);
The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputs the inversed value. The code contains errors. Find and fix the errors. Ex: If the input is 0.500, then the output is: The inverse of current = 1 / 0.500 = 2.000 1 import java.util.Scanner; 2 3 public class CurrentInverse { 4 5 6 7 8 9 10 11 12 13 14 15 16 17 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); /* Modify the following code */ int current; int currentInverse; current scnr.nextInt (); currentInverse = 1 / current; System.out.printf("The inverse of current = 1 / %.3f", current); System.out.printf(" = %.3f\n", currentInverse);
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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New Jave code must be entered inbetween grey blocks of code as seen in photo
![The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputs
the inversed value. The code contains errors. Find and fix the errors.
Ex: If the input is 0.500, then the output is:
The inverse of current = 1 / 0.500 = 2.000
1 import java.util.Scanner;
3 public class CurrentInverse {
N&00
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Pee
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public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
/* Modify the following code */
int current;
int currentInverse;
current scnr.nextInt ();
currentInverse = 1 / current;
System.out.printf("The inverse of current = 1 / %.3f", current);
System.out.printf(" = %.3f\n", currentInverse);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0cc153ae-b205-4fb2-9991-7cf6a21d5016%2F851b1444-99e9-4a5c-a9ef-2763d400cc96%2Fgj71gg4_processed.png&w=3840&q=75)
Transcribed Image Text:The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputs
the inversed value. The code contains errors. Find and fix the errors.
Ex: If the input is 0.500, then the output is:
The inverse of current = 1 / 0.500 = 2.000
1 import java.util.Scanner;
3 public class CurrentInverse {
N&00
2
4
5
6
7
8
9
10
11
12
13
14
15
16
Pee
67
17
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
/* Modify the following code */
int current;
int currentInverse;
current scnr.nextInt ();
currentInverse = 1 / current;
System.out.printf("The inverse of current = 1 / %.3f", current);
System.out.printf(" = %.3f\n", currentInverse);
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