The inverse Laplace transform of f(t)=[sin (r)g(t)dr ƒ (t)= sin(t-x)g(r)dr ƒ (t)= †8(r)dr G(s) F(s) = 3² +1 f(t) = sin (r) dr using the Convolution theorem is
The inverse Laplace transform of f(t)=[sin (r)g(t)dr ƒ (t)= sin(t-x)g(r)dr ƒ (t)= †8(r)dr G(s) F(s) = 3² +1 f(t) = sin (r) dr using the Convolution theorem is
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The inverse Laplace transform of
f(t)= [sin (r)g(r)dr
f(1) =sin(t-r)g(r)di
s(t)={g(z)dr
G(s)
F(s) = 3² +1
f(t)= [sin (r) dr
using the Convolution theorem is
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