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The inverse Fourier transform of the following signal is, X(jø)=36cos (16@+60°) 18 (a) [e/*3(1+16)+e* 8 (t–16)] (b) 18[e/® 8(t+16)+e"j0®* 8 (t–16)] (c) [e/" 5(t-16)+e"* 8(t +16)] (d) 18[e/®® 5 (t–16)+e 5®° 5 (1 +16)] 18

The inverse Fourier transform of the following signal is, X(jø)=36cos (16@+60°) 18 (a) [e/*3(1+16)+e* 8 (t–16)] (b) 18[e/® 8(t+16)+e"j0®* 8 (t–16)] (c) [e/" 5(t-16)+e"* 8(t +16)] (d) 18[e/®® 5 (t–16)+e 5®° 5 (1 +16)] 18

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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The inverse Fourier transform of the following signal is, X(jø)=36cos (16@+60°) 18 (a) [e/*3(1+16)+e* 8 (t–16)] (b) 18[e/® 8(t+16)+e"j0®* 8 (t–16)] (c) [e/ 5(t–16)+e"* 8 (t +16)] (d) 18[e/* 5 (t–16)+e 1* 5 (t+16)] 18
Transcribed Image Text:The inverse Fourier transform of the following signal is, X(jø)=36cos (16@+60°) 18 (a) [e/*3(1+16)+e* 8 (t–16)] (b) 18[e/® 8(t+16)+e"j0®* 8 (t–16)] (c) [e/ 5(t–16)+e"* 8 (t +16)] (d) 18[e/* 5 (t–16)+e 1* 5 (t+16)] 18
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