The inverse forms of the results in Problem 49 in Exercises 7.1 are s-a {$ { (5-3)² + b²}= and eat cos bt <((-3)² + ²) = sin be. =eat Use the Laplace transform and these inverses to solve the given initial-value problem.
The inverse forms of the results in Problem 49 in Exercises 7.1 are s-a {$ { (5-3)² + b²}= and eat cos bt <((-3)² + ²) = sin be. =eat Use the Laplace transform and these inverses to solve the given initial-value problem.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The inverse forms of the results in Problem 49 in Exercises 7.1 are
^{²
{2}.
and
s-a
(sa)² + b²)
y(t)
c{₁5-2)
b
=
eat cos bt
= eat sin bt.
(sa)² + b²
Use the Laplace transform and these inverses to solve the given initial-value problem.
y' + y = et cos 3t, y(0) = 0
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