The inverse forms of the results in Problem 49 in Exercises 7.1 are and s-a y(t) = .(sa)² + b² } -3t eat b (sa)² + b² Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e cos bt = eat eat sin bt. cos 2t, y(0) = 0
The inverse forms of the results in Problem 49 in Exercises 7.1 are and s-a y(t) = .(sa)² + b² } -3t eat b (sa)² + b² Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e cos bt = eat eat sin bt. cos 2t, y(0) = 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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10Pls box the final answer
![The inverse forms of the results in Problem 49 in Exercises 7.1 are
and
s-a
x^{{{8-352)² + b ² }
y(t) =
b
(s - a +62
2
Use the Laplace transform
y' + y = e
-3t
=
=
eat
cos bt
eat sin bt.
and these inverses to solve the given initial-value problem.
cos 2t, y(0) = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1f6e2b8-f1b7-42f3-bc5f-abb383883a0b%2Ff494667b-1a2c-4bb8-b794-97582ddb2de1%2Fvyqfgpq_processed.png&w=3840&q=75)
Transcribed Image Text:The inverse forms of the results in Problem 49 in Exercises 7.1 are
and
s-a
x^{{{8-352)² + b ² }
y(t) =
b
(s - a +62
2
Use the Laplace transform
y' + y = e
-3t
=
=
eat
cos bt
eat sin bt.
and these inverses to solve the given initial-value problem.
cos 2t, y(0) = 0
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