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The inverse forms of the results in Problem 49 in Exercises 7.1 are 2² / and s-a (sa)² + b² y(t) = b = e cos bt 6²} ((sa)² + b²] Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e-4t cos 3t, y(0) = 0 = eat sin bt.

The inverse forms of the results in Problem 49 in Exercises 7.1 are 2² / and s-a (sa)² + b² y(t) = b = e cos bt 6²} ((sa)² + b²] Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e-4t cos 3t, y(0) = 0 = eat sin bt.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The inverse forms of the results in Problem 49 in Exercises 7.1 are and s-a 2² / (√5 - 2)² + b ² y(t) = b (sa)² + b² 6²} = eat cos bt = eat sin bt. Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e-4t cos 3t, y(0) = 0
Transcribed Image Text:The inverse forms of the results in Problem 49 in Exercises 7.1 are and s-a 2² / (√5 - 2)² + b ² y(t) = b (sa)² + b² 6²} = eat cos bt = eat sin bt. Use the Laplace transform and these inverses to solve the given initial-value problem. y' + y = e-4t cos 3t, y(0) = 0
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