The interval from -2.19 to 1.80 captures an area of 0.95 under the z curve. This implies that another large-sample 95% confidence interval for has lower limit x -2.19 and upper limit x + 1.80 Would you recommend using this 95% interval over the 95% interval x + 1.96 √nVndiscussed in the text? Explain. (Hint: Look at the width of each interval.)The new 95% interval has width (Need Help?Read ItvnThe 95% interval discussed in the text has width. The new interval is wider thanvn✔✔✔ the interval discussed in the text, so the new interval would not be recommended

Given that the new 95% interval is x¯-2.19σn, x¯+1.80σn and the 95% interval discussed in the text…

Answered: The interval from -2.19 to 1.80…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Time left 2:00:56 Suppose the interval [-3.52, 5.06] represents the 95% confidence interval to estimate -H2,Which of the following statements is true: O A. There is significant evidence of a difference in the mean for these two groups. O B. The true population means of the two groups are independent O C. None of these O D. There is no significant evidence of a difference between the mean for these two groups
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.5, and the sample standard deviation, s, is found to be 4.6. Click the icon to view the table of areas under the t-distribution. Next Question (a) Construct a 95% confidence interval about u if the sample size, n, is 34. Lower bound: 17.89 ; Upper bound: 21.11 (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about u if the sample size, n, is 51. Lower bound: Upper bound: (Use ascending order. Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer 4 parts remaining Clear All Type here to search DELL F10 F9 F8 F7 F6 F5 F3 4) F4 K4 F2 & 8o 立

Thirty-four small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 41.1 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit 1 upper limit 2 margin of error 3 (b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit 4 upper limit 5 margin of error 6 (c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit 7 upper limit 8 margin of error 9 (d) Compare the margins of…
Step 3 The necessary value for Za/2 was determined to be 1.645. Recall the given information. Sample 1 n1 = 400 P1 = 0.56 P2 = 0.41 Substitute these values to first find the lower bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) 1 72 lower bound = P₁-P₂-²a/2 = 0.560.41 Sample 2 n2 = 300 = 0.0559 = 0.56 0.41 = 02441 X Substitute these values to find the upper bound for the confidence interval, rounding the result to four decimal places. P₁(1-P₁) P₂(1-P₂) upper bound = P₁ P₂ + ²a/2√ n1 n2 X + ✔ - 1.645, + 0.56(1 0.56) 0.41(10.41) 300 +1.645. 400 0.56(1 0.56) + 400 + 0.41(1 0.41) 300
6.2.13 Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The sample mean is (Type an integer or a decimal.)
A simple random sample of size n is drawn. The sample mean, x, is found to be 18.4, and the sample standard deviation, s, is found to be 4.8. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about µ if the sample size, n, is 35. μ Lower bound: 16.75; Upper bound: 20.05 (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about µ if the sample size, n, is 61. μ Lower bound:; Upper bound: (Use ascending order. Round to two decimal places as needed.)
7.2.7-T Question Help Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value t/2, (b) find the critical value z,12, or (c) 40- state that neither the normal distribution nor the t distribution applies. 30- The confidence level is 90%, o= 4084 thousand dollars, and the histogram of 55 player salaries (in thousands of dollars) of football players on a team is as shown. 20어 10- 0- 4000 8000 12000 16000 20000 Salary (thousands of dollars) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. t/2= (Round to two decimal places as needed.) O B. Za/2 = (Round to two decimal places as needed.) C. Neither the normal distribution nor the t distribution applies. kɔuənbə
A sample of 14 male college students consumes an average of 14.3 gallons of beer per month, with a sample standard deviation of 5.2 gallons. You can safely assume that the population of monthly beer consumption is Normally distributed. What is the margin of error for a 90% Confidence Interval for the mean? (Leave your answer to two decimal places, ex: 18.12)
A simple random sample of size n is drawn. The sample mean, x, is found to be 17.7, and the sample standard deviation, s, is found to be 4.7. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 34. Lower bound: 16.06 ; Upper bound: 19.34 (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about u if the sample size, n, is 51. Lower bound: Upper bound: (Use ascending order. Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer. Clear All parts remaining
Construct a 95% confidence interval to estimate the population mean using the data below. x=38 s=11 n=39 With 95% confidence, when n=39 the population mean is between a lower limit of and an upper limit of (Round to two decimal places as needed.)
A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 206 milligrams with s = 12.7 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs. ___< µ < ____ (Round to one decimal places) (To ensure your final answer is correct do not round your error. Use the entire answer for the error shown in the calculator. Then after subtracting/adding the unrounded error to the sample mean, round your answer to 1 decimal place)
Suppose the 90% confidence interval for the mean SAT scores of applicants at a business college is given by [1,691, 1,838]. This confidence interval uses the sample mean and the sample standard deviation based on 25 observations. Use t value 1.711 in your calculations. [You may find it useful to reference the t table.] What are the sample mean and the sample standard deviation used when computing the interval? (Round final answers to 2 decimal places.) sample mean = 1,764.50 sample standard deviation=??? ANSWER IS NOT 358.95

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