Find the general solution of the differential equation: dy + (2xy – 4e¯*)dx = 0. What is the integrating factor? µ(x) = Use lower case c for the constant in answer below. y(x) = 2²+ce=z² %3D 4xe

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the general solution of the differential equation: dy+(2xy−4e−x2)dx=0dy+(2xy-4e-x2)dx=0.

What is the integrating factor? μ(x)=μ(x)= ex2Correct  

Use lower case cc for the constant in answer below.

y(x)=y(x)= 4xe−x2+ce−x2Incorrect  

(A) Find an integrating factor as a function of only one variable for the equation

ydx−xdy=0ydx-xdy=0.

μ(x)=μ(x)=1x​Incorrect  

(B) Solve the resulting exact equation
y(x)=y(x)=xcCorrect  

Find the general solution of the differential equation: dy + (2xy – 4e
)dæ = 0.
What is the integrating factor? µ(x) =
Use lower case c for the constant in answer below.
y(x) =
-r² + ce
4xe
Transcribed Image Text:Find the general solution of the differential equation: dy + (2xy – 4e )dæ = 0. What is the integrating factor? µ(x) = Use lower case c for the constant in answer below. y(x) = -r² + ce 4xe
(A) Find an integrating factor as a function of only one variable for the equation
ydx – xdy = 0.
1
μ(π)
(B) Solve the resulting exact equation
y(x)
xc
Transcribed Image Text:(A) Find an integrating factor as a function of only one variable for the equation ydx – xdy = 0. 1 μ(π) (B) Solve the resulting exact equation y(x) xc
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The Integrating factor is wrong, look back at question and notice that 1/x is wrong, it is supposed to be 1/(x^2)

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