The integral using horizontal rectangles which finds the volume obtained when the region bounded by z = y and z = √y is rotated about the line y = -4 is given by * √ ² v² - (√)²2 dy 2. π √² (v-4). (√y-y) dy 2. π + √²+ (y + 4). (√5 - y) dy (4-y)(√y-y) dy 1 2. * So ² (v- √² (v + 4). (v - √y) dy 2.7/²
The integral using horizontal rectangles which finds the volume obtained when the region bounded by z = y and z = √y is rotated about the line y = -4 is given by * √ ² v² - (√)²2 dy 2. π √² (v-4). (√y-y) dy 2. π + √²+ (y + 4). (√5 - y) dy (4-y)(√y-y) dy 1 2. * So ² (v- √² (v + 4). (v - √y) dy 2.7/²
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The integral using horizontal rectangles which finds the volume obtained when the region bounded by z = y and z = √y is
rotated about the line y = -4 is given by
= √ ₁ v² - (√)²2 dy
2. T
-4-
- √ ² (v-4)· (√U - y) dy
2. π
X
2. π
1
√ ² (v + 4) · ( √5 - y) dy
+ √² (4-y)(√y-y) dy
2. π
1
+ √ ² (v + 4). (v - √5) dy
2"
Transcribed Image Text:-1
O
The integral using horizontal rectangles which finds the volume obtained when the region bounded by z = y and z = √y is
rotated about the line y = -4 is given by
= √ ₁ v² - (√)²2 dy
2. T
-4-
- √ ² (v-4)· (√U - y) dy
2. π
X
2. π
1
√ ² (v + 4) · ( √5 - y) dy
+ √² (4-y)(√y-y) dy
2. π
1
+ √ ² (v + 4). (v - √5) dy
2
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