The integral tests says that if an=f(n), then the series 2 an is convergent if and only n =1 if the integral J F(x)dx is convergent as long as the function f is BLANK-1, BLANK- 2, and BLANK-3 on the interval X21. BLANK-1 Add your answer BLANK-2 Add your answer BLANK-3 Add your answer .T dx= lim x-2dx= lim -Tl+1¬1= lim +1 = 1 Since the integral converges and therefore the series 2 K=1 K? also converges, and <1+1=2. K=1 K2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The integral tests says that if an=f(n), then the series 2 an is convergent if and only
n =1
if the integral
J F(x)dx
is convergent as long as the function f is BLANK-1, BLANK-
2, and BLANK-3 on the interval X21.
BLANK-1
Add your answer
BLANK-2
Add your answer
BLANK-3
Add your answer
.T
dx= lim
x-2dx= lim -Tl+1¬1= lim
+1 = 1
Since
the integral converges and therefore the series 2
K=1 K?
also converges, and
<1+1=2.
K=1 K2
Transcribed Image Text:The integral tests says that if an=f(n), then the series 2 an is convergent if and only n =1 if the integral J F(x)dx is convergent as long as the function f is BLANK-1, BLANK- 2, and BLANK-3 on the interval X21. BLANK-1 Add your answer BLANK-2 Add your answer BLANK-3 Add your answer .T dx= lim x-2dx= lim -Tl+1¬1= lim +1 = 1 Since the integral converges and therefore the series 2 K=1 K? also converges, and <1+1=2. K=1 K2
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for integral test three conditions must be satisfied for the function i.e.  continuous, positive and decreasing.

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