The integer solution of the 2x³ + 7x – 4 = 0(mod 5), then а) х—4(тod 25) b) x = 1(mod 5) c) x = 16(mod 25 d) None of the above
The integer solution of the 2x³ + 7x – 4 = 0(mod 5), then а) х—4(тod 25) b) x = 1(mod 5) c) x = 16(mod 25 d) None of the above
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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