The insurance company did a survey to determine how prevalent 'buzzed driving' is. In a random sample of 300 drivers, they found that 126 of them admitted to driving after a few drinks (at or slightly below the legal limit) if they felt, in their own judgement, they were "not too drunk to drive". Construct a 99% confidence interval for the proportion of all drivers who engage in this risky behavior. Round ALL answers to 3 decimal places. To compute this CI, I will need to use the distribution (z or t). The critical value (from the table) that I need to compute the margin of error is: . The margin of error for my interval is: . The lower bound of my CI is: and the upper bound of my Ci is: .
The insurance company did a survey to determine how prevalent 'buzzed driving' is. In a random sample of 300 drivers, they found that 126 of them admitted to driving after a few drinks (at or slightly below the legal limit) if they felt, in their own judgement, they were "not too drunk to drive". Construct a 99% confidence interval for the proportion of all drivers who engage in this risky behavior. Round ALL answers to 3 decimal places. To compute this CI, I will need to use the distribution (z or t). The critical value (from the table) that I need to compute the margin of error is: . The margin of error for my interval is: . The lower bound of my CI is: and the upper bound of my Ci is: .
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The insurance company did a survey to determine how prevalent 'buzzed driving' is. In a random sample of 300 drivers, they found that 126 of them admitted to driving after a few drinks (at or slightly below the legal limit) if they felt, in their own judgement, they were "not too drunk to drive". Construct a 99% confidence interval for the proportion of all drivers who engage in this risky behavior.
Round ALL answers to 3 decimal places.
To compute this CI, I will need to use the distribution (z or t).
The critical value (from the table) that I need to compute the margin of error is: .
The margin of error for my interval is: .
The lower bound of my CI is: and the upper bound of my Ci is: .
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