The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.08 cm. Suppose the distribution of the diameter is normal,(Round your answers to four decimal places.)LAUSE SALT(a) Calculate P(7.99 sxs 8.01) when - 16.P(7.99 X 8.01) -(b) How likely is it that the sample mean diameter exceeds 8.01 when n = 257PX8.01)

Answered: The inside diameter of a randomly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In the entire population of a certain type of tree, the mean height of the trees is μ = 168.8 ft and the standard deviation is σ = 43.6 ft. You collect a random sample of n=22 trees. The distribution of these sample means is shown below. Each tick mark on the horizontal axis is a distance of one more standard error. Complete the indicated boxes, correct to two decimal places. mean of distribution=168.8 standard error=9.30 Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.
A normal distribution with a mean of 2mm and a standard deviation of 0.05mm a randomly generated number of 0.71 , need to calculate the standardised Z value, from my notes Z = (actual value - mean)/standard deviation. do i take the randomly generated number of 0.81 as the actual value ?
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Please help me with this problem. Thanks!
The sum of the squared deviation scores is SS = 247.6 for a population of N = 12 scores. What is the variance for this population? Be sure to submit a numeric response that is rounded to the nearest hundredth (2nd decimal place)
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