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The inside diameter of a randomly selected piston ring is a random variable with mean value 16 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) USE SALT (a) Calculate P(15.99 ≤ x ≤ 16.01) when n = 16. P(15.99 ≤x≤ 16.01) = [ (b) How likely is it that the sample mean diameter exceeds 16.01 when n = 25? P(X ≥ 16.01) =

The inside diameter of a randomly selected piston ring is a random variable with mean value 16 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) USE SALT (a) Calculate P(15.99 ≤ x ≤ 16.01) when n = 16. P(15.99 ≤x≤ 16.01) = [ (b) How likely is it that the sample mean diameter exceeds 16.01 when n = 25? P(X ≥ 16.01) =

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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The inside diameter of a randomly selected piston ring is a random variable with mean value 16 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) USE SALT (a) Calculate P(15.99 ≤x≤ 16.01) when n = 16. P(15.99 ≤ x ≤ 16.01) = (b) How likely is it that the sample mean diameter exceeds 16.01 when n = 25? P(X ≥ 16.01) =
Transcribed Image Text:The inside diameter of a randomly selected piston ring is a random variable with mean value 16 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) USE SALT (a) Calculate P(15.99 ≤x≤ 16.01) when n = 16. P(15.99 ≤ x ≤ 16.01) = (b) How likely is it that the sample mean diameter exceeds 16.01 when n = 25? P(X ≥ 16.01) =
The breaking strength of a rivet has a mean value of 10,050 psi and a standard deviation of 497 psi. USE SALT (a) What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9,950 and 10,250? (Round your answer to four decimal places.) (b) If the sample size had been 15 rather than 40, could the probability requested in part (a) be calculated from the given information? Explain your reasoning. O Yes, the probability in part (a) can still be calculated from the given information. No, n should be greater than 30 in order to apply the Central Limit Theorem. No, n should be greater than 20 in order to apply the Central Limit Theorem. No, n should be greater than 50 in order to apply the Central Limit Theorem.
Transcribed Image Text:The breaking strength of a rivet has a mean value of 10,050 psi and a standard deviation of 497 psi. USE SALT (a) What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9,950 and 10,250? (Round your answer to four decimal places.) (b) If the sample size had been 15 rather than 40, could the probability requested in part (a) be calculated from the given information? Explain your reasoning. O Yes, the probability in part (a) can still be calculated from the given information. No, n should be greater than 30 in order to apply the Central Limit Theorem. No, n should be greater than 20 in order to apply the Central Limit Theorem. No, n should be greater than 50 in order to apply the Central Limit Theorem.
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