The inner and outer surfaces of a pane of plain glass, which is 0.4 cm thick and has an area of 2 m x 2 m, have a temperature of 20°C and 5°C, respectively. Heat conduction coefficients can be found in the table in the following picture a) Calculate the amount of energy that is lost as heat through the window pane during 10 hours. b) Calculate the amount of energy that is lost as heat in the same period of time if a window consists of two panes of glass with the same area and 0.4 cm thickness, with an air gap of 1.2 cm between the panes of glass
The inner and outer surfaces of a pane of plain glass, which is 0.4 cm thick and has an area of 2 m x 2 m, have a temperature of 20°C and 5°C, respectively. Heat conduction coefficients can be found in the table in the following picture a) Calculate the amount of energy that is lost as heat through the window pane during 10 hours. b) Calculate the amount of energy that is lost as heat in the same period of time if a window consists of two panes of glass with the same area and 0.4 cm thickness, with an air gap of 1.2 cm between the panes of glass
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The inner and outer surfaces of a pane of plain glass, which is 0.4 cm thick and has an area of 2 m x 2 m, have a temperature of 20°C and 5°C, respectively. Heat conduction coefficients
can be found in the table in the following picture
a) Calculate the amount of energy that is lost as heat through the window pane during 10 hours.
b) Calculate the amount of energy that is lost as heat in the same period of time if a window consists of two
panes of glass with the same area and 0.4 cm thickness, with an air gap of 1.2 cm between
the panes of glass.
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