**Problem Statement:**The initially stationary 24-kg block is subjected to the time-varying force whose magnitude $P$ is shown in the plot. Note that the force is zero for all times greater than 5 s. Determine the time $t_s$ at which the block comes to rest.**Given Values:**\[\mu_k = 0.43 \quad \mu_s = 0.51 \quad 26^\circ\quad 24\, \text{kg}\]**Diagrams:**1. **Diagram of Block with Forces:** - A block weighing 24 kg is placed on a surface inclined at an angle of 26 degrees. - The coefficient of kinetic friction ($\mu_k$) is 0.43. - The coefficient of static friction ($\mu_s$) is 0.51. - There is a force $P$ applied upwards along the ramp.2. **Plot of Force $P$ Against Time $t$:** - A graph is shown with Force $P$ (in N) on the vertical axis and Time $t$ (in s) on the horizontal axis. - From $t = 0$ to $t = 5$ seconds, the force $P$ increases linearly from 0 N to 173 N. - For times greater than 5 seconds, the force $P$ is constant at 0 N.**Answer:**\[t_s = \boxed{4.181} \, \text{s}\]

To find: The time at which the block comes to the rest. Given: The mass of the block is m=24 kg. The…

The initially stationary 24-kg block is subjected to the time-varying force whose magnitude P is shown in the plot. Note that the force is zero for all times greater than 5 s. Determine the time to at which the block comes to rest. H₂=0.43 Hs = 0.51 Answe: ts= i 24 kg 4.181 P 26° P. N 173 0 5 t, s

The initially stationary 24-kg block is subjected to the time-varying force whose magnitude P is shown in the plot. Note that the force is zero for all times greater than 5 s. Determine the time to at which the block comes to rest. H₂=0.43 Hs = 0.51 Answe: ts= i 24 kg 4.181 P 26° P. N 173 0 5 t, s

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Forming and Shaping

Metal forming is a category of metalworking process through which the material can be given the desired shape and size by subjecting it to plastic deformation, where the component undergoes bulk deformation process upon application of loads. Unlike the shearing and machining process, the material does not undergo up to a failure point as indicated in the stress-strain curve. Hence, the stresses induced during the forming process are greater than yield strength but less than the failure strength of the material. The process does not lead to the loss of material, so it can be said to be an economical process. During forming, the material is subjected to tensile forces, compressive forces, bending, and shearing loading conditions. The material should possess the property of ductility to undergo the forming process.

Question

**Problem Statement:**

The initially stationary 24-kg block is subjected to the time-varying force whose magnitude $P$ is shown in the plot. Note that the force is zero for all times greater than 5 s. Determine the time $t_s$ at which the block comes to rest.

**Given Values:**

\[
\mu_k = 0.43 \quad \mu_s = 0.51 \quad 26^\circ\quad 24\, \text{kg}
\]

**Diagrams:**

1. **Diagram of Block with Forces:**
- A block weighing 24 kg is placed on a surface inclined at an angle of 26 degrees.
- The coefficient of kinetic friction ($\mu_k$) is 0.43.
- The coefficient of static friction ($\mu_s$) is 0.51.
- There is a force $P$ applied upwards along the ramp.

2. **Plot of Force $P$ Against Time $t$:**
- A graph is shown with Force $P$ (in N) on the vertical axis and Time $t$ (in s) on the horizontal axis.
- From $t = 0$ to $t = 5$ seconds, the force $P$ increases linearly from 0 N to 173 N.
- For times greater than 5 seconds, the force $P$ is constant at 0 N.

**Answer:**

\[
t_s = \boxed{4.181} \, \text{s}
\]

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