The inequality P(3 ≤ x ≤ 5) contains the x-values 3, 4, and 5. We can use Table 2 to find the cumulative probability P(x ≤ 5), which contains the x-values 0, 1, 2, 3, 4, and 5. To get to P(3 ≤ x ≤ 5), we need to subtract the x-values 0, 1, and 2, or P(x s [ from the list. Rewrite P(3 ≤ x ≤ 5) in terms of two separate cumulative probabilities. P(3 ≤ x ≤ 5) = P(x ≤ 5) - P(x s
The inequality P(3 ≤ x ≤ 5) contains the x-values 3, 4, and 5. We can use Table 2 to find the cumulative probability P(x ≤ 5), which contains the x-values 0, 1, 2, 3, 4, and 5. To get to P(3 ≤ x ≤ 5), we need to subtract the x-values 0, 1, and 2, or P(x s [ from the list. Rewrite P(3 ≤ x ≤ 5) in terms of two separate cumulative probabilities. P(3 ≤ x ≤ 5) = P(x ≤ 5) - P(x s
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 23E
Related questions
Question
![Table 2 Cumulative Poisson Probabilities
Tabulated values are P(x = k) = = p(0) + p(1) + • • • + p(k).
(Computations are rounded to the third decimal place.)
k
0
1
2
3
4
5
6
7
k
0
1
2
3
4
5
CASO INMH7
6
7
8
9
10
11
12
13
14
15
16
17
.1
.905
.995
1.000
2.0
.135
.406
.677
.857
.947
.983
.995
.999
1.000
.2
.819
.982
.999
1.000
2.5
.082
.287
.544
.758
.891
.958
.986
.996
.999
1.000
.3
.741
.963
.996
1.000
3.0
.050
.199
.423
.647
.815
.916
.966
.988
.996
.999
1.000
.4
.670
.938
.992
.999
1.000
3.5
.033
.136
.321
.537
.725
.858
.935
.973
.990
.997
.999
1.000
.5
.607
.910
.986
.998
1.000
4.0
.018
.092
.238
.433
.629
.785
.889
.949
.979
.992
.997
.999
1.000
μl
.6
.549
.878
.977
.997
1.000
μ
4.5
.011
.061
.174
.342
.532
.703
.831
.913
.960
.983
.993
.998
.999
1.000
.7
.497
.844
.966
.994
.999
1.000
5.0
.007
.040
.125
.265
.440
.616
.762
.867
.932
.968
.986
.995
.998
.999
1.000
.8
.449
.809
.953
.991
.999
1.000
5.5
.004
.027
.088
.202
.358
.529
.686
.809
.894
.946
.975
.989
.996
.998
.999
1.000
.9
.407
.772
.937
.987
.998
1.000
6.0
.003
.017
.062
.151
.285
.446
.606
.744
.847
.916
.957
.980
.991
.996
.999
.999
1.000
1.0
.368
.736
.920
.981
.996
.999
1.000
6.5
.002
.011
.043
.112
.224
.369
.563
.673
.792
.877
.933
.966
.984
.993
.997
.999
1.000
1.5
.223
.558
.809
.934
.981
.996
.999
1.000
7.0
.001
.007
.030
.082
.173
.301
.450
.599
.729
.830
.901
.947
.973
.987
.994
.998
.999
1.000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc303f822-5e20-4d30-8920-178170554c96%2F25e26b34-3129-41c2-9921-a5c78c71bdee%2F4ynxit_processed.png&w=3840&q=75)
Transcribed Image Text:Table 2 Cumulative Poisson Probabilities
Tabulated values are P(x = k) = = p(0) + p(1) + • • • + p(k).
(Computations are rounded to the third decimal place.)
k
0
1
2
3
4
5
6
7
k
0
1
2
3
4
5
CASO INMH7
6
7
8
9
10
11
12
13
14
15
16
17
.1
.905
.995
1.000
2.0
.135
.406
.677
.857
.947
.983
.995
.999
1.000
.2
.819
.982
.999
1.000
2.5
.082
.287
.544
.758
.891
.958
.986
.996
.999
1.000
.3
.741
.963
.996
1.000
3.0
.050
.199
.423
.647
.815
.916
.966
.988
.996
.999
1.000
.4
.670
.938
.992
.999
1.000
3.5
.033
.136
.321
.537
.725
.858
.935
.973
.990
.997
.999
1.000
.5
.607
.910
.986
.998
1.000
4.0
.018
.092
.238
.433
.629
.785
.889
.949
.979
.992
.997
.999
1.000
μl
.6
.549
.878
.977
.997
1.000
μ
4.5
.011
.061
.174
.342
.532
.703
.831
.913
.960
.983
.993
.998
.999
1.000
.7
.497
.844
.966
.994
.999
1.000
5.0
.007
.040
.125
.265
.440
.616
.762
.867
.932
.968
.986
.995
.998
.999
1.000
.8
.449
.809
.953
.991
.999
1.000
5.5
.004
.027
.088
.202
.358
.529
.686
.809
.894
.946
.975
.989
.996
.998
.999
1.000
.9
.407
.772
.937
.987
.998
1.000
6.0
.003
.017
.062
.151
.285
.446
.606
.744
.847
.916
.957
.980
.991
.996
.999
.999
1.000
1.0
.368
.736
.920
.981
.996
.999
1.000
6.5
.002
.011
.043
.112
.224
.369
.563
.673
.792
.877
.933
.966
.984
.993
.997
.999
1.000
1.5
.223
.558
.809
.934
.981
.996
.999
1.000
7.0
.001
.007
.030
.082
.173
.301
.450
.599
.729
.830
.901
.947
.973
.987
.994
.998
.999
1.000
![Step 5
rp(xs)
The inequality P(3 ≤ x ≤ 5) contains the x-values 3, 4, and 5. We can use Table 2 to find the cumulative probability P(x ≤ 5), which contains the x-values 0, 1, 2, 3, 4, and 5. To get to P(3 ≤ x ≤ 5), we need to subtract the x-values 0, 1, and 2, or P x ≤
from the list.
Rewrite P(3 ≤ x ≤ 5) in terms of two separate cumulative probabilities.
P(3 ≤ x ≤ 5) = P(x ≤ 5) – Px ≤
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc303f822-5e20-4d30-8920-178170554c96%2F25e26b34-3129-41c2-9921-a5c78c71bdee%2F0s5fmzg_processed.png&w=3840&q=75)
Transcribed Image Text:Step 5
rp(xs)
The inequality P(3 ≤ x ≤ 5) contains the x-values 3, 4, and 5. We can use Table 2 to find the cumulative probability P(x ≤ 5), which contains the x-values 0, 1, 2, 3, 4, and 5. To get to P(3 ≤ x ≤ 5), we need to subtract the x-values 0, 1, and 2, or P x ≤
from the list.
Rewrite P(3 ≤ x ≤ 5) in terms of two separate cumulative probabilities.
P(3 ≤ x ≤ 5) = P(x ≤ 5) – Px ≤
-
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