The inductive step of an inductive proof shows that for k>0, if k+1 ₁02=2+1 -1, then Σ22 =2+2 -1. In which step of j=0 the proof is the inductive hypothesis used? 277 O Step 2 O Step 1 31,627 O Step 3 O Step 4 Σ+ 2 = Στο 2 + 2+1 j=0 j=0 k+1 23 j=0 k+1 2 j=0 k+1 Σ2 j=0 (Step 1) = (2k+1 − 1) + 2k+1 (Step 2) = 2.2k+1 - 1 = 2k+2 -1 (Step 3) (Step 4) % DEC G C

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Discrete Math
The inductive step of an inductive proof shows that for k≥ 0, if
02=2+1 -1, then Σ22 =2+2 -1. In which step of
k+1
j=0
the proof is the inductive hypothesis used?
277
#3
E
D
O Step 2
O Step 1
O Step 3
31,627
O Step 4
54
$
Στ 23
Στο 23
k+1 2
j=0
R
F
+1
Σ2
%
T
j=0
Στo 2 + 2+1
= (2k+1 − 1) + 2k+1
= 2.2k+1 − 1
= 2+2 -1
G
=
A
G Search or type URL
zoom
6
MacBook Pro
Y
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&
7
*
U
DEC
13 O
* 0
(Step 1)
(Step 2)
(Step 3)
(Step 4)
8
J
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K
0
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€
P
Transcribed Image Text:The inductive step of an inductive proof shows that for k≥ 0, if 02=2+1 -1, then Σ22 =2+2 -1. In which step of k+1 j=0 the proof is the inductive hypothesis used? 277 #3 E D O Step 2 O Step 1 O Step 3 31,627 O Step 4 54 $ Στ 23 Στο 23 k+1 2 j=0 R F +1 Σ2 % T j=0 Στo 2 + 2+1 = (2k+1 − 1) + 2k+1 = 2.2k+1 − 1 = 2+2 -1 G = A G Search or type URL zoom 6 MacBook Pro Y T & 7 * U DEC 13 O * 0 (Step 1) (Step 2) (Step 3) (Step 4) 8 J | - 9 K 0 L € P
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