The inductive step of an inductive proof shows that for k>0, if k+1 ₁02=2+1 -1, then Σ22 =2+2 -1. In which step of j=0 the proof is the inductive hypothesis used? 277 O Step 2 O Step 1 31,627 O Step 3 O Step 4 Σ+ 2 = Στο 2 + 2+1 j=0 j=0 k+1 23 j=0 k+1 2 j=0 k+1 Σ2 j=0 (Step 1) = (2k+1 − 1) + 2k+1 (Step 2) = 2.2k+1 - 1 = 2k+2 -1 (Step 3) (Step 4) % DEC G C
The inductive step of an inductive proof shows that for k>0, if k+1 ₁02=2+1 -1, then Σ22 =2+2 -1. In which step of j=0 the proof is the inductive hypothesis used? 277 O Step 2 O Step 1 31,627 O Step 3 O Step 4 Σ+ 2 = Στο 2 + 2+1 j=0 j=0 k+1 23 j=0 k+1 2 j=0 k+1 Σ2 j=0 (Step 1) = (2k+1 − 1) + 2k+1 (Step 2) = 2.2k+1 - 1 = 2k+2 -1 (Step 3) (Step 4) % DEC G C
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Discrete Math

Transcribed Image Text:The inductive step of an inductive proof shows that for k≥ 0, if
02=2+1 -1, then Σ22 =2+2 -1. In which step of
k+1
j=0
the proof is the inductive hypothesis used?
277
#3
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O Step 2
O Step 1
O Step 3
31,627
O Step 4
54
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Στ 23
Στο 23
k+1 2
j=0
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+1
Σ2
%
T
j=0
Στo 2 + 2+1
= (2k+1 − 1) + 2k+1
= 2.2k+1 − 1
= 2+2 -1
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