The inductive step of an inductive proof shows that for k > 0, if 2 = 2*+1 - 1, then 2 = 2k+2 -1. In which step of the proof is the inductive hypothesis used? %3D k+1 j%3D0 +1 2i = o 2 + 2*+1 (Step 1) %3D しjー 3(2*+1-1) + 2*+1 (Step 2) = 2 - 2k+1 – 1 (Step 3) = 2k+2 – 1 (Step 4) %3D Step 1 Step 2 Step 3 O Step 4

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The inductive step of an inductive proof shows that for k 2 0, if o 2 = 2k+1-1, then
2 = 2k+2 - 1. In which step of the proof is the inductive hypothesis used?
k+1
%3D
E 2 = E, 2i + 2*+1 (Step 1)
(2*+1 - 1) + 2*+1
(Step 2)
%3D
= 2 - 2k+1 – 1
(Step 3)
= 2k+2 – 1
(Step 4)
O Step 1
O Step 2
Step 3
Step 4
Transcribed Image Text:The inductive step of an inductive proof shows that for k 2 0, if o 2 = 2k+1-1, then 2 = 2k+2 - 1. In which step of the proof is the inductive hypothesis used? k+1 %3D E 2 = E, 2i + 2*+1 (Step 1) (2*+1 - 1) + 2*+1 (Step 2) %3D = 2 - 2k+1 – 1 (Step 3) = 2k+2 – 1 (Step 4) O Step 1 O Step 2 Step 3 Step 4
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