The indicated function y₁(x) is a solution of the given differential equation. e-SP(x) dx y} (x) Y₂=Y₁(x) [² Y₂ = -dx (5) as instructed, to find a second solution y₂(x). (1 - 2x - x²)y" + 2(1 + x)y' – 2y = 0; y₁ = x + 1 -

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The indicated function \( y_1(x) \) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,

\[
y_2 = y_1(x) \int \frac{e^{-\int P(x) \, dx}}{y_1^2(x)} \, dx \quad (5)
\]

as instructed, to find a second solution \( y_2(x) \).

\[
(1 - 2x - x^2)y'' + 2(1 + x)y' - 2y = 0; \quad y_1 = x + 1
\]

\[ 
y_2 =
\]

[In the space provided, the solution \( y_2 \) should be calculated and entered.] 

This text can be used as part of an educational resource for students learning how to solve differential equations using reduction of order. The equation given is a second-order linear differential equation with variable coefficients. The goal is to find a second linearly independent solution \( y_2(x) \) using a known solution \( y_1(x) \).
Transcribed Image Text:The indicated function \( y_1(x) \) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2, \[ y_2 = y_1(x) \int \frac{e^{-\int P(x) \, dx}}{y_1^2(x)} \, dx \quad (5) \] as instructed, to find a second solution \( y_2(x) \). \[ (1 - 2x - x^2)y'' + 2(1 + x)y' - 2y = 0; \quad y_1 = x + 1 \] \[ y_2 = \] [In the space provided, the solution \( y_2 \) should be calculated and entered.] This text can be used as part of an educational resource for students learning how to solve differential equations using reduction of order. The equation given is a second-order linear differential equation with variable coefficients. The goal is to find a second linearly independent solution \( y_2(x) \) using a known solution \( y_1(x) \).
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