The index of refraction for a certain type of glass is 1.645 for blue light and 1.605 for red light. A beam of white light (one tha contains all colors) enters a plate of glass from the air, nair ≈ 1, at an incidence angle of 36.55°. What is the absolute value of he angle in the glass between blue and red parts of the refracted beams? lal-

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**Educational Content: Light Refraction and Dispersion in Glass**

**Problem Statement:**

Given:
- The index of refraction for a certain type of glass is \(1.645\) for blue light and \(1.605\) for red light.
- A beam of white light (one that contains all colors) enters a plate of glass from the air, \(n_{\text{air}} \approx 1\), at an incidence angle of \(36.55^\circ\).

**Question:**
What is the absolute value of \(\delta\), the angle in the glass, between the blue and red parts of the refracted beams?

**Solution:**

To solve this problem, we use Snell's Law, which states:

\[
n_{\text{air}} \cdot \sin(\theta_{\text{air}}) = n_{\text{glass}} \cdot \sin(\theta_{\text{glass}})
\]

1. **Calculate the refraction angle for blue light (\(\theta_{\text{blue}}\)):**

Using Snell's Law:

\[
1 \cdot \sin(36.55^\circ) = 1.645 \cdot \sin(\theta_{\text{blue}})
\]

Solving for \(\theta_{\text{blue}}\):

\[
\sin(\theta_{\text{blue}}) = \frac{\sin(36.55^\circ)}{1.645}
\]

2. **Calculate the refraction angle for red light (\(\theta_{\text{red}}\)):**

Using Snell's Law:

\[
1 \cdot \sin(36.55^\circ) = 1.605 \cdot \sin(\theta_{\text{red}})
\]

Solving for \(\theta_{\text{red}}\):

\[
\sin(\theta_{\text{red}}) = \frac{\sin(36.55^\circ)}{1.605}
\]

3. **Calculate \(|\delta|\):**

\[
|\delta| = |\theta_{\text{blue}} - \theta_{\text{red}}|
\]

**Final Step:**

Calculate the values and find the absolute difference to determine \(|\delta|\).

---

**Interactive Component:**

Use the text box below to input your calculated value for \(|\delta|\).

\[ |\delta| = \_\_^\circ \]

---

This problem illustrates the concept
Transcribed Image Text:**Educational Content: Light Refraction and Dispersion in Glass** **Problem Statement:** Given: - The index of refraction for a certain type of glass is \(1.645\) for blue light and \(1.605\) for red light. - A beam of white light (one that contains all colors) enters a plate of glass from the air, \(n_{\text{air}} \approx 1\), at an incidence angle of \(36.55^\circ\). **Question:** What is the absolute value of \(\delta\), the angle in the glass, between the blue and red parts of the refracted beams? **Solution:** To solve this problem, we use Snell's Law, which states: \[ n_{\text{air}} \cdot \sin(\theta_{\text{air}}) = n_{\text{glass}} \cdot \sin(\theta_{\text{glass}}) \] 1. **Calculate the refraction angle for blue light (\(\theta_{\text{blue}}\)):** Using Snell's Law: \[ 1 \cdot \sin(36.55^\circ) = 1.645 \cdot \sin(\theta_{\text{blue}}) \] Solving for \(\theta_{\text{blue}}\): \[ \sin(\theta_{\text{blue}}) = \frac{\sin(36.55^\circ)}{1.645} \] 2. **Calculate the refraction angle for red light (\(\theta_{\text{red}}\)):** Using Snell's Law: \[ 1 \cdot \sin(36.55^\circ) = 1.605 \cdot \sin(\theta_{\text{red}}) \] Solving for \(\theta_{\text{red}}\): \[ \sin(\theta_{\text{red}}) = \frac{\sin(36.55^\circ)}{1.605} \] 3. **Calculate \(|\delta|\):** \[ |\delta| = |\theta_{\text{blue}} - \theta_{\text{red}}| \] **Final Step:** Calculate the values and find the absolute difference to determine \(|\delta|\). --- **Interactive Component:** Use the text box below to input your calculated value for \(|\delta|\). \[ |\delta| = \_\_^\circ \] --- This problem illustrates the concept
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