The indeterminate frame below is loaded with gravity loads as shown. Using MOMENT DISTRIBUTION METHOD, compute for the internal moments and moment reaction occurring on the structure due to the applied loads. Show your complete solution from the computation of distribution factor, fixed end moments, balancing, unbalanced moments and total joint moment for each member. Neglect effects of side-sway in the calculation. Use up to Bal5. Determine the FF. 1 Moment at joint E of column EH in kN-m. MEH 2. Moment at joint B of girder BC in kN-m. MBC 3. Relative stiffness of member BC. kBC 4. Distribution factor at joint A of girder AB. DFAB 5. Fixed end moment at joint D of girder DE in kN-m
The indeterminate frame below is loaded with gravity loads as shown. Using MOMENT DISTRIBUTION METHOD, compute for the internal moments and moment reaction occurring on the structure due to the applied loads. Show your complete solution from the computation of distribution factor, fixed end moments, balancing, unbalanced moments and total joint moment for each member. Neglect effects of side-sway in the calculation. Use up to Bal5. Determine the FF. 1 Moment at joint E of column EH in kN-m. MEH 2. Moment at joint B of girder BC in kN-m. MBC 3. Relative stiffness of member BC. kBC 4. Distribution factor at joint A of girder AB. DFAB 5. Fixed end moment at joint D of girder DE in kN-m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The indeterminate frame below is loaded with gravity loads as shown. Using MOMENT DISTRIBUTION METHOD, compute for the internal moments and moment reaction occurring on the structure due to the applied loads. Show your complete solution from the computation of distribution factor, fixed end moments, balancing, unbalanced moments and total joint moment for each member. Neglect effects of side-sway in the calculation. Use up to Bal5.
Determine the FF.
1 Moment at joint E of column EH in kN-m. MEH
2. Moment at joint B of girder BC in kN-m. MBC
3. Relative stiffness of member BC. kBC
4. Distribution factor at joint A of girder AB. DFAB
5. Fixed end moment at joint D of girder DE in kN-m. FEMDE
DONT FORGET THAT THE GIVEN VALUES ARE
a=7.0
b= 23.5
c= 2.9
d= 5.2
e= 7.3
SHOW YOUR COMPLETE SOLUTION AND DRAWING. THANK YOU
Transcribed Image Text:a KN/m
b KN
2.4 m
A
C
21
31
41
31
51
b KN
3.6 m
a KN/m
D
E
F
21
31
41
31
51
G
H
e m
em
dm
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