The illustration above represents a mixture of hydrogen (blue) and oxygen (red) molecules. If the molecules in the illustration react according to the following equation, 2 H₂ + O₂ → 2 H ₂0 2 there would be molecule(s) of H₂ 2 4,0, 1, 02 4, 1, 0,02 4,0, 1, H₂ 4, 1, 0, H₂ molecule(s) of H₂O formed. There would also be ______ molecule(s) of O₂ and excess (leftover). In reaction miting ant is
The illustration above represents a mixture of hydrogen (blue) and oxygen (red) molecules. If the molecules in the illustration react according to the following equation, 2 H₂ + O₂ → 2 H ₂0 2 there would be molecule(s) of H₂ 2 4,0, 1, 02 4, 1, 0,02 4,0, 1, H₂ 4, 1, 0, H₂ molecule(s) of H₂O formed. There would also be ______ molecule(s) of O₂ and excess (leftover). In reaction miting ant is
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:The illustration above represents a mixture of hydrogen (blue) and oxygen (red) molecules.
If the molecules in the illustration react according to the following equation, \(2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O}\), there would be _____ molecule(s) of \(\text{H}_2\text{O}\) formed. There would also be _____ molecule(s) of \(\text{O}_2\) and _____ molecule(s) of \(\text{H}_2\) in excess (leftover). In this particular reaction, the limiting reactant is _____.
Options:
- \(4, 0, 1, \text{O}_2\)
- \(4, 1, 0, \text{O}_2\) (selected)
- \(4, 0, 1, \text{H}_2\)
- \(4, 1, 0, \text{H}_2\)
Diagram Explanation:
The diagram shows a balanced mixture of diatomic hydrogen and oxygen molecules. There are four diatomic hydrogen molecules (blue) and two diatomic oxygen molecules (red), which can react to form four water molecules (\(\text{H}_2\text{O}\)). The limiting reactant in this setup is \(\text{O}_2\), as all molecules of oxygen are used up in the reaction, leaving no excess \(\text{O}_2\) and one excess \(\text{H}_2\).
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