the hypothesis that o_A^2=o_B^2 against o_A^2#o_B^2 at a level of significance a=0.05. Does this mean that one instrument is more reliable than the other? Or are they equally accurate?
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- Professor Doja Cat conducted an experiment with 24 participants who are asked to respond to one of three categories. Her chi-squared obtained turns out to be 9.92, which is statistically significant. What is the correct way to report this finding? X^2(2, N=24) = 9.92, p < .05 X^2(3, N=22) = 9.92, p < .05 X^2(2, 24) = 9.92, p < .05 X^2(4, N=24) = 9.92, p > .05Follow the steps in Test of Hypothesis (pic) including your conclusion and round off the critical value and test statistic 4 decimal places Two suppliers manufacture a plastic gear used in a laser printer. The impact strength of these gears measures in foot-pounds is an important characteristic. A random sample of 10 gears from supplier 1 results in x1 = 290 and s1 = 12 while another random sample of 16 gears from the second supplier results in x2 = 321 and s2 = 22. Is there evidence to support the claim that supplier 2 provides gears with higher mean impact strength. Use a =0.04, and assume that both populations are normally distributed with equal variances.2. Among the 50 Geography students, 44 students passed the course of Univariate Statistics in Geography. In other words, the pass rate for Geography students was 44/50=0.88. The overall course pass rate for all students who took GEO 211 was 0.91. (a) Do you think the pass rate of Geography students was lower than the overall value? Choose a = 0.05 (b) What is the p-value
- You'd like to test the null hypothesis that the means of the two samples (column A and column B) are the same. The alternative hypothesis is that they are not the same. You have no reason to believe that the standard deviations of the two samples are equal. Test at the alpha = 0.10 level. After using Excel, what do you conclude? Are the means the same?Vertical banded gastroplasty is a surgical procedure that reduces the volume of the stomach in order to produce weight loss. In a recent study, 82 patients with Type 2 diabetes underwent this procedure, and 59 of them experienced a recovery from diabetes. Does this study provide convincing evidence that less than 75% of those with diabetes who undergo this surgery will recover from diabetes? Use the =α0.10 level of significance and the P-value method with the TI-84 Plus calculator. STATE THE NULL AND ALT HYPTrue or False
- Only Answer Question 15. Question 15 has parts to it, would love all the parts to be answered please.A sample is selected from a population with population mean = 50 After a treatment is administered to the individuals in the sample, the mean is found to be M = 55 and the variance is s ^ 2 = 64 a. If the sample has n = 36 scores, then conduct the four steps of hypothesis testing to evaluate the significance of the treatment effect and calculate Cohen's d to measure the size of the treatment effectUse a two-tailed test with alpha fevel = .05Question 19 A manufacture makes light-weight sneakers, and claim that the average weight of one sneaker is no bigger than 2 pounds. To verify this claim, a sample of 9 sneakers are weighed, and the sample mean is 2.4 pounds with the sample variance of 0.25 pounds^2. Assuming the weights of sneakers are normally distributed, we would like to test the claim of the manufacture at 10% level of significance. Please select the correct statement from below:
- Use dataset "HT_4143.xls" and conduct a two-sample t-test using Excel. You'd like to test the null hypothesis that the means of the two samples (column A and column B) are the same. The alternative hypothesis is that they are not the same. You have no reason to believe that the standard deviations of the two samples are equal. Test at the alpha = 0.10 level. After using Excel, what do you conclude? Are the means the same? Group of answer choices You reject the null hypothesis. Therefore, you conclude that the means of the two populations are different. You reject the null hypothesis. Therefore, you conclude that the means of the two populations are the same. You cannot reject the null hypothesis. Therefore, you conclude that the means of the two populations are different. You cannot reject the null hypothesis. Therefore, you conclude that the means of the two populations are the same. HT_ 4143.xls: X1 X299.73 98.6995.93 98.9494.92 96.63100.52 99.16101.28…A teacher has a large container of blue, red, and green beads. She reports to the students that the proportion of blue beads in the container is 0.30. The students feel the proportion of blue beads is lower than 0.30. A student randomly selects 60 beads and finds that 12 of the beads are blue. The P-value for the test of the hypotheses, H_{0} / p = 0.30 and H_{a} / p < 0.30 , is 0.045. What is the correct interpretation of this value? There is a 4.5% chance the proportion of blue beads in the container is 0.3. Assuming the true proportion of blue beads in the container is 0.30, there is a 4.5% probability that the null hypothesis is true. Assuming the true proportion of blue beads in the container is 0.30, there is a 4.5% probability that the sample proportion would be 0.20 or less by chance alone. Assuming the true proportion of blue beads in the container is less than 0.30, there is a 4.5% probability that the sample proportion would be 0.20 or less by chance alone.You'd like to test the null hypothesis that the means of the two samples (column A and column B) are the same. The alternative hypothesis is that they are not the same. You have no reason to believe that the standard deviations of the two samples are equal. Test at the alpha = 0.10 level. After using Excel, what do you conclude? Are the means the same?