Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![**Question:**
The hydroxide ion concentration in household ammonia is \(3.2 \times 10^{-3} \, \text{M}\) at \(25 \, ^\circ\text{C}\). What is the concentration of hydronium ions in the solution?
**Explanation:**
To determine the concentration of hydronium ions (\([\text{H}_3\text{O}^+]\)) in the solution, we can use the following relationship derived from the water dissociation constant (\(K_w\)):
\[ K_w = [\text{H}_3\text{O}^+][\text{OH}^-] \]
At \(25 \, ^\circ\text{C}\), the value of \(K_w\) is \(1.0 \times 10^{-14} \, \text{M}^2\).
Given the hydroxide ion concentration (\([\text{OH}^-]\)):
\[ [\text{OH}^-] = 3.2 \times 10^{-3} \, \text{M} \]
We can rearrange the expression to solve for the hydronium ion concentration:
\[ [\text{H}_3\text{O}^+] = \frac{K_w}{[\text{OH}^-]} \]
Substitute the known values:
\[ [\text{H}_3\text{O}^+] = \frac{1.0 \times 10^{-14} \, \text{M}^2}{3.2 \times 10^{-3} \, \text{M}} \]
Now, perform the calculation:
\[ [\text{H}_3\text{O}^+] = \frac{1.0 \times 10^{-14}}{3.2 \times 10^{-3}} = 3.125 \times 10^{-12} \, \text{M} \]
Therefore, the concentration of hydronium ions in the solution is \(3.125 \times 10^{-12} \, \text{M}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa9e8573f-552b-4431-b931-fec80f931989%2F4aee2c30-8ac3-4454-8a5c-cee66ba346fb%2Fc419q_processed.png&w=3840&q=75)
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