The hydrolysis of pyrophosphate to orthophosphate drives biosynthetic reactions such as DNA synthesis. In Escherichia coli, a pyrophosphatase catalyzes this hydrolytic reaction. The pyrophosphatase has a mass of 120 kDa and consists of six identical subunits. A unit of activity for this enzyme, U, is the amount of enzyme that hydrolyzes 10 µmol of pyrophosphate in 15 minutes. The purified enzyme has a Vmax of 2800 U per milligram of enzyme. When [S] >> KM, how many micromoles of substrate can 1 mg of enzyme hydrolyze per second? Vmax [E]T 1.12 ×10¹1 If each enzyme subunit has one active site, how many micromoles of active sites, or [E]T, are there in 1 mg of enzyme? Keat Incorrect || 8.33 x10³ What is the turnover number, or keat, of the enzyme? Incorrect μmol. sl. mg-1 1.34 X107 μmol-mg-1

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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Q11:

## Enzyme Kinetics: Pyrophosphatase in E. coli

**Overview:**

The hydrolysis of pyrophosphate to orthophosphate is crucial for biosynthetic reactions such as DNA synthesis. In *Escherichia coli*, this reaction is catalyzed by pyrophosphatase. Understanding the kinetics of this enzyme involves calculating several parameters including V_max, [E]_T, and k_cat.

1. **V_max Calculation:**

   - **Question:** When [S] >> K_M, how many micromoles of substrate can 1 mg of enzyme hydrolyze per second?
   - **User Input:** 1.12 × 10^11 μmol · s^-1 · mg^-1
   - **Status:** Incorrect

2. **[E]_T Calculation:**

   - **Question:** If each enzyme subunit has one active site, how many micromoles of active sites, or [E]_T, are there in 1 mg of enzyme?
   - **User Input:** 8.33 × 10^3 μmol · mg^-1
   - **Status:** Incorrect

3. **k_cat Calculation:**

   - **Question:** What is the turnover number, or k_cat, of the enzyme?
   - **User Input:** 1.34 × 10^7 s^-1
   - **Status:** Incorrect

**Diagram Explanation:**

The image provides text input boxes for each of the calculations. The user entered values are highlighted in light gray with a red border indicating incorrect answers.

### Important Notes:
- V_max represents the maximum rate of reaction when the enzyme is saturated with substrate.
- [E]_T defines the total enzyme concentration.
- k_cat, the turnover number, indicates the number of substrate molecules converted per enzyme molecule per second.

Understanding these parameters helps elucidate the enzyme's efficiency and catalytic capacity in cellular processes.
Transcribed Image Text:## Enzyme Kinetics: Pyrophosphatase in E. coli **Overview:** The hydrolysis of pyrophosphate to orthophosphate is crucial for biosynthetic reactions such as DNA synthesis. In *Escherichia coli*, this reaction is catalyzed by pyrophosphatase. Understanding the kinetics of this enzyme involves calculating several parameters including V_max, [E]_T, and k_cat. 1. **V_max Calculation:** - **Question:** When [S] >> K_M, how many micromoles of substrate can 1 mg of enzyme hydrolyze per second? - **User Input:** 1.12 × 10^11 μmol · s^-1 · mg^-1 - **Status:** Incorrect 2. **[E]_T Calculation:** - **Question:** If each enzyme subunit has one active site, how many micromoles of active sites, or [E]_T, are there in 1 mg of enzyme? - **User Input:** 8.33 × 10^3 μmol · mg^-1 - **Status:** Incorrect 3. **k_cat Calculation:** - **Question:** What is the turnover number, or k_cat, of the enzyme? - **User Input:** 1.34 × 10^7 s^-1 - **Status:** Incorrect **Diagram Explanation:** The image provides text input boxes for each of the calculations. The user entered values are highlighted in light gray with a red border indicating incorrect answers. ### Important Notes: - V_max represents the maximum rate of reaction when the enzyme is saturated with substrate. - [E]_T defines the total enzyme concentration. - k_cat, the turnover number, indicates the number of substrate molecules converted per enzyme molecule per second. Understanding these parameters helps elucidate the enzyme's efficiency and catalytic capacity in cellular processes.
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