The high-level function strcpy copies the character string src to the character string dst. void strcpy(char dst[], char src[]) { int i = 0; do { dst[i] = src[i]; } while (src[i++]); } Q1.1 Implement the strcpy function in MIPS assembly code. Use $se for i. A Please select file(s) Select file(s)
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![Q1
The high-level function strcpy copies the character string src to the character string dst.
void strcpy(char dst[], char src[]) {
int i = 0;
do {
dst[i]
} while (src[i++]); }
= src[i];
Q1.1
Implement the strcpy function in MIPS assembly code. Use $se for i.
Please select file(s)
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![Q1.2
Draw a picture of the stack before, during, and after the strcpy function call.
Assume $sp = 0X7FFFFF00 just before strcpy is called.
Please select file(s)
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- MIPS Programming Assignment Part I Rewrite C statements int i = 11; int j = 10; int A[] = { 0x11, 0x22, 0x33 }; int B[] = { 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 }; B[ 8 ] = A[ i - j ]; in MIPS assembly. Assume that addresses of variables i, j, A, and B are loaded into the registers $s3, $s4, $s6, and $s7, respectively: .data i: .word 11 j: .word 10 A: .word 0x11, 0x22, 0x33 B: .word 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 .text la $s3, i # load address of i la $s4, j # load address of j la $s6, A # load address of A la $s7, B # load address of B When you finished programming, add a comment at the end of your code which specifies what value is assigned to the location of B[8] after the program executes. Part IIWrite MIPS Assembly program that allows the user to enter a string of text. Determine whether the entered string is a palindrome (a word or a phrase that reads the same backward as forward, like "kayak" and "level") and print the result on the screen.Code required in mips assembly language not a c code required Write a MIPS procedure that takes as its two parameters the starting address of a (zero-terminated) string, and a character c, and removes all instances of the character from the string. Also, write a main program to test your procedure. Your main program should input a string from the user (you can assume that the string will be at most 40 characters, not including the zero byte delimiter), and then prompt for input of a character c. If the character c that the user inputs is the newline character (ascii code 10), your program should terminate. Otherwise, your program should invoke your procedure, output the modified string, and then prompt for input of another character to be removed from the string, continuing in this manner until the input character is the newline character.COMPUTER ORGANISATION : Use RARS simulator to write and execute the two codes below using RISC-V Assembly language.
- 2) Translate the function origami into a MIPS assembly code fragment: int origami (int Aŋ, int BØ, int a2) { int to = 0; int vo = 0; int t1; do { t1 = A[t0]; if (t1 >= 0) { B[v0] = A[t0]; vo++; to++; } while (t0please convert the code to C program #include <bits/stdc++.h> using namespace std; //FIND(X) int find(int X, vector<int>& parent) { if (parent[X] == X) return X; return find(parent[X], parent); } //UNION(X,Y) void UNION(int X, int Y, vector<int>& parent) { parent[Y] = X; } int main() { int n, m; cout << "Enter number of edges\n"; cin >> n; cout << "Enter number of nodes\n"; cin >> m; //edges list //each edge is a vector [u,v] vector<vector<int> > edges(n); for (int i = 0; i < n; i++) { int u, v; cout << "info for edge " << i + 1 << endl; cout << "Enter source node u: "; cin >> u; cout << "Enter destination node v: "; cin >> v; edges[i] = vector<int>{ u, v }; } vector<int> parent(m + 1); for (int i = 1; i <= m; i++) parent[i] = i; for (auto edge : edges) { //find set name for source node, u int x = find(edge[0], parent); //cout<<x<<endl;…Electrical Engineering Consider a function called Vocals. This function has as parameter the starting address of a string of characters. The function calculates the number of times the 'a' character appears (in lowercase) in the string. In case of passing the mull string the function returns the value -1. In case the string does not have any 'a', the function returns 0. It is requested: 1. Program using the assembler 8086 the code of the Vocal function 2. Program using the ARM assembler the code of the Vocal functionObjectives • Implement loop in MIPS assembly code • Implement decision statement in MIPS assembly code Implement array in MIPS assembly code • Pass array as a function parameter and access it in a function in MIPS assembly code • Process array data in MIPS assembly code Task Implement and call the following C-style function in MIPS assembly code. You do not have to worry about invalid values of n. The min() function int min(int n, int x[]){ int minval; int i; minval = x[0]; for (i=1; iConvert this code to RISC-V 64 gcc assembly language #include <stdio.h> char inputText[] = "babibabbbiiibabibiba";char pattern[] = "bi";const int patternSize = 2;const int inputSize = 20; int main(){ int lps[patternSize]; lps[0] = 0; int len = 0; int i = 1, j = 0; while (i < patternSize) { if (pattern[i] == pattern[len]) { len++; lps[i] = len; i++; } else { if (len != 0) { len = lps[len - 1]; } else { lps[i] = 0; i++; } } } i = 0; while (i < inputSize) { if (pattern[j] == inputText[i]) { j++; i++; } if (j == patternSize) { printf("Found pattern at index %d \n", i - j); j = lps[j - 1]; } else if (i < inputSize && pattern[j] != inputText[i]) {…COMPUTER ORGANISATION :: Use RARS simulator to write and execute the two codes below using RISC-V Assembly language.Instruction: Explain the function of the program line by line thoroughly.Program: #include <iostream> using namespace std; //Swap functionvoid swap(int *xp, int *yp){ int temp = *xp; *xp = *yp; *yp = temp;} void selectionSort(int arr[], int n){ int i, j, min_idx; // One by one move boundary of // unsorted subarray for (i = 0; i < n-1; i++) { // Find the minimum element in // unsorted array min_idx = i; for (j = i+1; j < n; j++) if (arr[j] < arr[min_idx]) min_idx = j; // Swap the found minimum element // with the first element if(min_idx!=i) swap(&arr[min_idx], &arr[i]); }} //Function to print an arrayvoid printArray(int arr[], int size){ int i; for (i=0; i < size; i++) cout << arr[i] << " "; cout << endl;} int main(){ int x, n; cout << "Enter number of integers: "; cin >>n; int *arr = new int(n); for (int i = 0; i < n; i++) { cout << " Enter Integer No. " << (i + 1) << ": ";…OpenMP C++ With the following code, create 3 versions: Outer loop parallelism: use a single OpenMP pragma only at the outer loop Inner loop parallelism: use a single OpenMP pragma only at the inner loop (use reduction) Nested loop parallelism: use pragmas at both the outer loop and inner loop ----- #pragma omp parallel for for(int i = 0; i < n; i++) { #pragma omp parallel for for(int j = 0; j < n; j++) { y[i] += A[i * n + j] * x[j]; } }2. Consider the two main variables: Number and N. Number is a 1024 byte variable. It represents a huge unsigned integer. N is a 4 byte variable. It represents the number of bits by which the number will be shifted. assenbly language Write an SHL1024 function that receives two parameters on the stack: the address of a number of 1024 bytes and a value giving by how many bits the number of 1024 bytes will be shifted towards the left. This function must act like an SHL but on a 1024 byte variable. On return, the content of the Number variable will be shifted to the left by the number of bits demand. On return, the values of the general registers and the EFLAGS should be the same as before the call to SHL1024SEE MORE QUESTIONSRecommended textbooks for youC++ Programming: From Problem Analysis to Program…Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage LearningC++ Programming: From Problem Analysis to Program…Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning