The Henry's Law constant for hydrogen sulphide (H;S) in water (H;0) at 25 °C is 5.5 x 10° kPa. a. Calculate how much H;S is dissolved in water in mg H;S/ litre H;0 if the partial pressure of H;S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1; 0:16.

Introduction to Chemical Engineering Thermodynamics
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The Henry's Law constant for hydrogen sulphide (H;S) in water (H;0) at 25 °C is 5.5 x 10° kPa.
a. Calculate how much H;S is dissolved in water in mg H;S/ litre H;0 if the partial pressure
of H;S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1;
0:16.
Transcribed Image Text:The Henry's Law constant for hydrogen sulphide (H;S) in water (H;0) at 25 °C is 5.5 x 10° kPa. a. Calculate how much H;S is dissolved in water in mg H;S/ litre H;0 if the partial pressure of H;S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1; 0:16.
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