The Henry’s Law constant for hydrogen sulphide (H2S) in water (H2O) at 25 ⁰C is 5.5 x 104 kPa. a. Calculate how much H2S is dissolved in water in mg H2S/ litre H2O if the partial pressure of H2S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1; O:16. b. Why is Henry’s Law more suitable than Raoult’s Law to calculate how much H2S is dissolved in water in this particular case?

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