The heights of a random sample of 50 college students showed a mean of 181.6 centimeters and a standard deviation of 6.9 centimeters.(a) Construct a 98% confidence interval for the mean height of all college students.(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 181.6 centimeters?Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.Click here to view page 1 of the table of critical values of the t-distribution.Click here to view page 2 of the table of critical values of the t-distribution......(a) The confidence interval is <µ<.(Round to two decimal places as needed.)

Answered: The heights of a random sample of 50…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A data set includes 106 body temperatures of healthy adult humans having a mean of 98.9°F and a standard deviation of 0.62°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view at distribution table Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table What is the confidence interval estimate of the population mean u? ***** (Round to three decimal places as needed) What does this suggest about the use of 98.6°F as the mean body temperature? OA. This suggests that the mean body temperature is lower than 98.6°F OB. This suggests that the mean body temperature could very possibly be 98.6°F OC. This suggests that the mean body temperature is higher than 98.6°F
A random sample of 47 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $17.51 per car. The population standard deviation is $6.05. Estimate the mean bill for all cars from the drive thru with 91% confidence.
An analyst found that the average amount of money in bank accounts at his/her bank is $2,000 with a standard deviation of $150. What would be the variance?
The distribution of the student heights at a large college is approximately bell shaped. If the mean height is 66 inches,and approximately 95% of the heights fall between 32 and 100 inches, then, the standard deviation of the heightdistribution is approximately equal to
When we make a set of measurements, the width or standard deviation of the sampled parent distribution generally reflects the accuracy of our measurement methods. True or False
The gas mileage for a new model of car is normally distributed, with a standard deviation of 3.5 miles per gallon. If only 4% of the cars have a gas mileage of above 20 mpg, what is the mean of the distribution
The Alpha company takes a survey of the age for all employees. The average age is 35 with a standard deviation of 3.2 years. The results for a normal distribution curve. If the company has 985 workers, how many are over 44 years old?
A random sample of 18 light bulbs is drawn from a normally distributed population. The population has mean and standard deviation are 517 hours and 39 hours, respectively. What is the mean of the sampling distribution the sample mean?
CetaceaNow is a conservationist organization that monitors the health of whale and dolphin populations worldwide. As part of their work, they are modelling the lengths of blue whale calves that will be born over the next decade. For their model, CetaceaNow is using a normal distribution with a mean of 280 in and a standard deviation of 20 in Use this table or the ALEKS calculator to find the percentage of blue whale calves with a length of between 269 in and 299 in according to the model. For your intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example 98.23%).
A random sample of 12 graduates of a certain secretarial school typed an average of 82.6 words per minute with a standard deviation of 8.1 words per minute. Assuming a normal distribution for the number of words typed per minute, find a 95% confidence interval for the average number of words typed by all graduates of this school. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. The confidence interval is <μ< (Round to two decimal places as needed.)

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