The height of a tree is defined as the number of edges on the longest path in the tree. The function shown in the pseudocode below is invoked as height(root) to compute the height of a binary tree rooted at the tree pointer root. int height { if (n if (n → left if (n → right (treeptr n) NULL) return -1; 3D%3D NULL) == NULL) return 0; =D%3D else return B1 // Box 1 else { h1 height (n → left); if (n → right NULL) == return (1+h1); else { h2 return | B2| ; height (n –→ right); // Box 2 } } } The appropriate expressions for the two boxes B1 and B2 are Select one: a. B1: (1 + height (n right)) B2: (1 + max (h1, h2)) O b. B1: (height (n right)) B2: (1 + max (h1,h2)) O c. B1: height (n right) B2: max (h1, h2) O d. B1: (1 + height (n right)) B2: max (h1, h2)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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c++

The height of a tree is defined as the number of edges on the longest path in the tree. The function shown in the pseudocode
below is invoked as height(root) to compute the height of a binary tree rooted at the tree pointer root.
int height (treeptr n)
{ if (n
NULL)
return -1;
3D%3D
if (n → left
NULL)
==
if (n → right
NULL) return 0;
=D3=
else return
B1
// Box 1
else { hl
height
if (n → right
return (1+h1);
(n → left);
NULL)
==
else { h2
height (n –→ right);
return
B2
// Box 2
}
}
}
The appropriate expressions for the two boxes B1
and B2 are
Select one:
O a. B1: (1 + height (n → right)) B2: (1 + max (h1, h2))
O b. B1: (height (n → right)) B2: (1 + max (h1, h2))
O c. B1: height (n → right) B2: max (h1, h2)
O d. B1: (1 + height (n → right)) B2: max (h1, h2)
Transcribed Image Text:The height of a tree is defined as the number of edges on the longest path in the tree. The function shown in the pseudocode below is invoked as height(root) to compute the height of a binary tree rooted at the tree pointer root. int height (treeptr n) { if (n NULL) return -1; 3D%3D if (n → left NULL) == if (n → right NULL) return 0; =D3= else return B1 // Box 1 else { hl height if (n → right return (1+h1); (n → left); NULL) == else { h2 height (n –→ right); return B2 // Box 2 } } } The appropriate expressions for the two boxes B1 and B2 are Select one: O a. B1: (1 + height (n → right)) B2: (1 + max (h1, h2)) O b. B1: (height (n → right)) B2: (1 + max (h1, h2)) O c. B1: height (n → right) B2: max (h1, h2) O d. B1: (1 + height (n → right)) B2: max (h1, h2)
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