The height of a falling object above the ground after t seconds can be modeled by a quadratic function. A ball is thrown directly upward from a height of 48 feet. The ball's position above the ground after 1 and 2 seconds is shown in the following table: Time Position above the ground 48 1 64 2 48 Find the quadratic function that fits this data. Select one: O a. s(t) = 16t2 - 32t - 48 O b. s(t) = -16t2 + 32t + 48 O c. s(t) = 6t2 + 12t + 48 O d. s(t) = -6t2 – 12t – 48

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The height of a falling object above the ground after t seconds can be modeled by a quadratic
function. A ball is thrown directly upward from a height of 48 feet. The ball's position above
the ground after 1 and 2 seconds is shown in the following table:
Time
Position above the ground
48
1
64
2
48
Find the quadratic function that fits this data.
Select one:
O a. s(t) = 16t2 - 32t - 48
O b. s(t) = -16t2 + 32t + 48
O c. s(t) = 6t2+ 12t + 48
O d. s(t) = -6t2 – 12t – 48
Transcribed Image Text:The height of a falling object above the ground after t seconds can be modeled by a quadratic function. A ball is thrown directly upward from a height of 48 feet. The ball's position above the ground after 1 and 2 seconds is shown in the following table: Time Position above the ground 48 1 64 2 48 Find the quadratic function that fits this data. Select one: O a. s(t) = 16t2 - 32t - 48 O b. s(t) = -16t2 + 32t + 48 O c. s(t) = 6t2+ 12t + 48 O d. s(t) = -6t2 – 12t – 48
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