The height of a certain type of palm tree is normally distributed with mean 45 feet and standard deviation 10 feet. A random sample of fifteen of these palm trees are observed. It is of interest to determine the probability that a single palm tree has a height of more than 50 feet. Identify the correct formula for solving. P (X > 50) (50-45) 10 VI5 = P Z > P (X > 50) (45-50) 10 V15 = P(Z > P(X > 50) = P (Z > (50-45) 10 О Р(X > 50) — P(z> (45-50) 10 P (X > 50) (50-45) 100 V15 = P ( Z > О Р(X > 50) (50-45) 100 = P O P(X > 50) = P ( z > (50-45) 10 None of the above /Unable to solve
The height of a certain type of palm tree is normally distributed with mean 45 feet and standard deviation 10 feet. A random sample of fifteen of these palm trees are observed. It is of interest to determine the probability that a single palm tree has a height of more than 50 feet. Identify the correct formula for solving. P (X > 50) (50-45) 10 VI5 = P Z > P (X > 50) (45-50) 10 V15 = P(Z > P(X > 50) = P (Z > (50-45) 10 О Р(X > 50) — P(z> (45-50) 10 P (X > 50) (50-45) 100 V15 = P ( Z > О Р(X > 50) (50-45) 100 = P O P(X > 50) = P ( z > (50-45) 10 None of the above /Unable to solve
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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
Transcribed Image Text:The height of a certain type of palm tree is normally distributed with mean 45 feet and standard deviation 10 feet. A random sample of fifteen of
these palm trees are observed. It is of interest to determine the probability that a single palm tree has a height of more than 50 feet. Identify the
correct formula for solving.
P (X > 50) = P ( z
(50–45)
10
V15
P (X > 50) = P
Z >
(45–50)
10
V15
Р (X > 50) — Р (Z>
(50–45)
10
V15
O P(X > 50) = P ( Z
(45–50)
10
(50–45)
P (X > 50) = P (z
Z >
100
V15
O P(X > 50) = P ( Z
(50–45)
100
O P(X > 50) = P ( Z
(50–45)
10
O None of the above / Unable to solve
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