The heating element of a coffeemaker operates at 120 V and carries a current of 2.50 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.740 kg of wate from room temperature (23.0°C) to the boiling point. min

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### Heating Element Problem

The heating element of a coffeemaker operates at 120 V and carries a current of **2.50 A**. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat **0.740 kg** of water from room temperature (23.0°C) to the boiling point.

[Input box for answer] min

---

In this problem, you are tasked with determining the amount of time it will take for the coffeemaker to heat the specified mass of water using the given electrical parameters. Consider the following steps to solve the problem:

1. **Calculate the Power Output:**
   - Use the formula \( P = IV \) where \( I \) is the current (2.50 A) and \( V \) is the voltage (120 V).

2. **Determine the Energy Required:**
   - Use the formula \( Q = mc\Delta T \) where \( m \) is the mass of the water, \( c \) is the specific heat capacity of water (approximately 4.186 J/g°C), and \( \Delta T \) is the change in temperature.

3. **Find the Time:**
   - Use the total energy required divided by the power output to find the time in seconds, and then convert it to minutes.

This structured approach will guide you in solving the problem effectively.
Transcribed Image Text:### Heating Element Problem The heating element of a coffeemaker operates at 120 V and carries a current of **2.50 A**. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat **0.740 kg** of water from room temperature (23.0°C) to the boiling point. [Input box for answer] min --- In this problem, you are tasked with determining the amount of time it will take for the coffeemaker to heat the specified mass of water using the given electrical parameters. Consider the following steps to solve the problem: 1. **Calculate the Power Output:** - Use the formula \( P = IV \) where \( I \) is the current (2.50 A) and \( V \) is the voltage (120 V). 2. **Determine the Energy Required:** - Use the formula \( Q = mc\Delta T \) where \( m \) is the mass of the water, \( c \) is the specific heat capacity of water (approximately 4.186 J/g°C), and \( \Delta T \) is the change in temperature. 3. **Find the Time:** - Use the total energy required divided by the power output to find the time in seconds, and then convert it to minutes. This structured approach will guide you in solving the problem effectively.
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