The heating element in an iron has a resistance 360. The iron is plugged into a 120-V outlet. What is the power dissipated by the iron?

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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**Problem Statement:**

The heating element in an iron has a resistance of 36Ω. The iron is plugged into a 120-V outlet. What is the power dissipated by the iron?

**Answer Section:**

- **Number**: [Text box for numerical input]
- **Units**: [Drop-down menu for unit selection]

This problem involves calculating the power dissipated by an electrical device using the formula for electrical power. The resistance and voltage values provided are essential to solve this problem using the appropriate formula:

\[ \text{Power} (P) = \frac{V^2}{R} \]

Where \( V \) is the voltage (120 V) and \( R \) is the resistance (36 Ω).
Transcribed Image Text:**Problem Statement:** The heating element in an iron has a resistance of 36Ω. The iron is plugged into a 120-V outlet. What is the power dissipated by the iron? **Answer Section:** - **Number**: [Text box for numerical input] - **Units**: [Drop-down menu for unit selection] This problem involves calculating the power dissipated by an electrical device using the formula for electrical power. The resistance and voltage values provided are essential to solve this problem using the appropriate formula: \[ \text{Power} (P) = \frac{V^2}{R} \] Where \( V \) is the voltage (120 V) and \( R \) is the resistance (36 Ω).
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