The heat of fusion of ice is 79.7 cal/g. The heat of vaporization of water is 540 cal/g. Report the answer using the correct number of significant figures! 1. How much energy is required to melt 100.0 grams of ice? Mass of ice = 100.0g Heat of fusion of ice: 100,0g|79.7 call-(1970 cal) 2. How much energy is required to vaporize 234.5 g of water? 234.5g | 540cal |= :79.7 cal/g Answer: 7970 cal Mass of 234.59 Heat of vaporization & 540 callg 12 6630, 1.2663X105 (1.3 x 10³ cal Answer: 1.3 x 105 cal 3. If 30.6 calories are required to vaporize 25 g of a substance, what is the heat of vaporization of that substance? mass of substance: 25g Heat vaporization: 30

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Calculations for Temperature and Phase Change Worksheet
The heat of fusion of ice is 79.7 cal/g.
The heat of vaporization of water is 540 cal/g.
Report the answer using the correct number of significant figures!
1. How much energy is required to melt 100.0 grams of ice? Mass of ice = 100.0g
Heat of fusion of ice:
100,0 g 79.7cal-1970 cal
2. How much energy is required to vaporize 234.5 g of water?
234.5g | 540 cal |-
30.6 cal
259
1.224
1.2 cal/g
1266301 1.2663X105
(1.3 x 10³ cal
Answer: 1.3 x 105 cal
3. If 30.6 calories are required to vaporize 25 g of a substance, what is the heat of vaporization of
that substance?
mass of substance: 25g
Heat
vaporization: 30.6 cal
-500.0g (1 cal) (1.1008) =
до
- 550 Ca1/4.1845
79.7cal/g
Answer: 7970 cal
Mass of 234.59
Heat of vaporization: 540 cal/g
Answer: 1.2 cal/g
4. How much energy is removed from 500.0 g of water when the temperature is lowered by 1.10 °C?
-F550 cal
mass m = 500.09
AT= 1.10°C
1000.09 1Cal (3x) = 3.00×10²cal
3%
Q==ssocal
Answer: -550. cal (or -2.30 x 10³ J)
23.01.2-2,3012×10³
-2.30× 10³5
Icg|
5. How much energy is required to raise the temperature of 1000.0 g of water from 23.00 °C to
26.00 °C?
m=1000.09
Q=S.M.AT
S=1 cal/goe Teinal - Tinitial
T₁ = 23.00°C
12=26.00°C
Answer: 3.00 x 103 cal (or 1.26 x 10¹J)
1.26×10 J
26.00-23.00=3%
8° 3.00x 10³ cal 4 1845 11.2.5 52x104
I cal
6. The specific heat of copper is (0.0924 cal/g°C), how much energy is required to raise the
temperature of 10.0 g of copper by 100.0 °C?
0.0924 cal
10.09
(357) (100.086)
92.4 call
mass of copper: 109
Specific heat copper: 0.0924cal/g °C
Answer: 92.4 cal
Transcribed Image Text:Calculations for Temperature and Phase Change Worksheet The heat of fusion of ice is 79.7 cal/g. The heat of vaporization of water is 540 cal/g. Report the answer using the correct number of significant figures! 1. How much energy is required to melt 100.0 grams of ice? Mass of ice = 100.0g Heat of fusion of ice: 100,0 g 79.7cal-1970 cal 2. How much energy is required to vaporize 234.5 g of water? 234.5g | 540 cal |- 30.6 cal 259 1.224 1.2 cal/g 1266301 1.2663X105 (1.3 x 10³ cal Answer: 1.3 x 105 cal 3. If 30.6 calories are required to vaporize 25 g of a substance, what is the heat of vaporization of that substance? mass of substance: 25g Heat vaporization: 30.6 cal -500.0g (1 cal) (1.1008) = до - 550 Ca1/4.1845 79.7cal/g Answer: 7970 cal Mass of 234.59 Heat of vaporization: 540 cal/g Answer: 1.2 cal/g 4. How much energy is removed from 500.0 g of water when the temperature is lowered by 1.10 °C? -F550 cal mass m = 500.09 AT= 1.10°C 1000.09 1Cal (3x) = 3.00×10²cal 3% Q==ssocal Answer: -550. cal (or -2.30 x 10³ J) 23.01.2-2,3012×10³ -2.30× 10³5 Icg| 5. How much energy is required to raise the temperature of 1000.0 g of water from 23.00 °C to 26.00 °C? m=1000.09 Q=S.M.AT S=1 cal/goe Teinal - Tinitial T₁ = 23.00°C 12=26.00°C Answer: 3.00 x 103 cal (or 1.26 x 10¹J) 1.26×10 J 26.00-23.00=3% 8° 3.00x 10³ cal 4 1845 11.2.5 52x104 I cal 6. The specific heat of copper is (0.0924 cal/g°C), how much energy is required to raise the temperature of 10.0 g of copper by 100.0 °C? 0.0924 cal 10.09 (357) (100.086) 92.4 call mass of copper: 109 Specific heat copper: 0.0924cal/g °C Answer: 92.4 cal
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