The heart is effectively made up of two pumps that create flowthrough the human circulatory system as shown in the diagrambelow. Assume that a human heart is producing a flow rate of 5.5L/min. The pressure at the inlet of the left side of the heart is 6.0mm Hg and at the outlet is 110 mm Hg. The pressure at the inlet ofthe right side of the heart is 0.0 mm Hg and the outlet is 15 mm Hg.What is the total rate of work being done by the heart in J/s (W)?pulmonary circuit15 mm Hg0.0 mm HgheartR6.0 mm Hgsystemic circuit110 mm Hg

Answered: The heart is effectively made up of two…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Related questions

Question

The heart is effectively made up of two pumps that create flow
through the human circulatory system as shown in the diagram
below. Assume that a human heart is producing a flow rate of 5.5
L/min. The pressure at the inlet of the left side of the heart is 6.0
mm Hg and at the outlet is 110 mm Hg. The pressure at the inlet of
the right side of the heart is 0.0 mm Hg and the outlet is 15 mm Hg.
What is the total rate of work being done by the heart in J/s (W)?
pulmonary circuit
15 mm Hg
0.0 mm Hg
heart
R
6.0 mm Hg
systemic circuit
110 mm Hg

Expert Solution

Step 1

Introduction

A pump is a tool that moves fluids (drinks or gases), or occasionally slurries, via way of means of mechanical action, generally transformed from electric power into hydraulic power.

Given

The right side of the heart is considered the right pump and the left side of the heart is considered the left pump.

$\begin{array}{rcl} F l o w r a t e (Q) & = & 5.5 L / m i n \\ I n l e t p r e s s u r e f o r r i g h t p u m p (P_{i R}) & = & 0 m m H g \\ O u t l e t p r e s s u r e f o r r i g h t p u m p (P_{o R}) & = & 15 m m H g \\ I n l e t p r e s s u r e f o r l e f t p u m p (P_{i L)} & = & 6 m m H g \\ O u t l e t p r e s s u r e f o r l e f t p u m p (P_{o L}) & = & 110 m m H g \end{array}$