The half-life of 222 Rn is 4.2 days. A sample of 222 Rn is allowed to decay for 17.2 days and after this time 4.6 mM remained. What was the initial quantity of 222Rn? (Assume first order decay) t = 17,2 days ti = 0.693
The half-life of 222 Rn is 4.2 days. A sample of 222 Rn is allowed to decay for 17.2 days and after this time 4.6 mM remained. What was the initial quantity of 222Rn? (Assume first order decay) t = 17,2 days ti = 0.693
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The half-life of \(^{222}\text{Rn}\) is 4.2 days. A sample of \(^{222}\text{Rn}\) is allowed to decay for 17.2 days and after this time 4.6 mM remained. What was the initial quantity of \(^{222}\text{Rn}\)? (Assume first-order decay)
**Handwritten Notes:**
- \( t_{1/2} = \frac{0.693}{k} \)
- \( t = 17.2 \, \text{days} \)
**Explanation:**
This problem focuses on using the concept of half-life and first-order kinetics to determine the initial quantity of a radioactive substance. The half-life, \( t_{1/2} \), is the time taken for half of the radioactive nuclei in a sample to decay. In this scenario, you are given the half-life and the time over which decay occurs to find the initial concentration of the substance.
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