The half life for the radioactive decay of rubidium-87 to strontium-87 is 4.88 × 10¹0 years. Suppose nuclear chemical analysis shows that there is 0.428 mmol of strontium-87 for every 1.000 mmol of rubidium-87 in a certain sample of rock. Calculate the age of the rock. Round your answer to 2 significant digits. years 0 x10 X Ś
The half life for the radioactive decay of rubidium-87 to strontium-87 is 4.88 × 10¹0 years. Suppose nuclear chemical analysis shows that there is 0.428 mmol of strontium-87 for every 1.000 mmol of rubidium-87 in a certain sample of rock. Calculate the age of the rock. Round your answer to 2 significant digits. years 0 x10 X Ś
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter25: Nuclear Chemistry
Section: Chapter Questions
Problem 46PS
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![The half life for the radioactive decay of rubidium-87 to strontium-87 is 4.88 ×
10¹0
Suppose nuclear chemical analysis shows that there is 0.428 mmol of strontium-87 for every 1.000 mmol of rubidium-87 in a certain sample of rock. Calculate
the age of the rock.
Round your answer to 2 significant digits.
years
x
years.
S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8da34ee-becc-4500-8ad8-c484d34a0ad4%2F61e0ca82-7324-4dac-bed9-1687390a83ae%2Fnnmix2f_processed.png&w=3840&q=75)
Transcribed Image Text:The half life for the radioactive decay of rubidium-87 to strontium-87 is 4.88 ×
10¹0
Suppose nuclear chemical analysis shows that there is 0.428 mmol of strontium-87 for every 1.000 mmol of rubidium-87 in a certain sample of rock. Calculate
the age of the rock.
Round your answer to 2 significant digits.
years
x
years.
S
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