The Grocery Manufacturers of America reported that 66.00% of consumers read the ingredients listed on a product's label. Assume the population proportion is p = 0.66 and a sample of 450 consumers is selected from the population. a. Show the sampling distribution of the sample proportion p, where is the proportion of the sampled consumers who read the ingredients listed on a product's label. E(p): (to 2 decimals) (to 4 decimals) b. What is the probability that the sample proportion will be within ±0.03 of the population proportion (to 4 decimals)? c. Answer part (b) for a sample of 660 (to 4 decimals).

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The Grocery Manufacturers of America reported that 66.00% of consumers read the ingredients listed on a
product's label. Assume the population proportion is p = 0.66 and a sample of 450 consumers is selected
from the population.
a. Show the sampling distribution of the sample proportion, where is the proportion of the sampled
consumers who read the ingredients listed on a product's label.
E(p) =
(to 2 decimals)
op=
(to 4 decimals)
b. What is the probability that the sample proportion will be within ±0.03 of the population proportion (to 4
decimals)?
c. Answer part (b) for a sample of 660 (to 4 decimals).
Transcribed Image Text:The Grocery Manufacturers of America reported that 66.00% of consumers read the ingredients listed on a product's label. Assume the population proportion is p = 0.66 and a sample of 450 consumers is selected from the population. a. Show the sampling distribution of the sample proportion, where is the proportion of the sampled consumers who read the ingredients listed on a product's label. E(p) = (to 2 decimals) op= (to 4 decimals) b. What is the probability that the sample proportion will be within ±0.03 of the population proportion (to 4 decimals)? c. Answer part (b) for a sample of 660 (to 4 decimals).
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