The graph shows three plots of velocity (Vo) versus substrate concentration ([S]). Determine which curve represents an enzyme' reaction velocity without any inhibitor present, which curve represents the velocity in the presence of a noncompetitive inhibitor, and which curve represents the velocity in the presence of a competitive inhibitor. Vmax Vmax Answer Bank competitive inhibitor no inhibitor

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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Q16:

The graph shows three plots of velocity (vo) versus substrate concentration ([S]). Determine which curve represents an enzyme's
reaction velocity without any inhibitor present, which curve represents the velocity in the presence of a noncompetitive
inhibitor, and which curve represents the velocity in the presence of a competitive inhibitor.
max
Vmax
Vo
Select all of the true statements.
[S] (₂M)
Answer Bank
competitive inhibitor
no inhibitor
noncompetitive inhibitor
A higher substrate concentration is associated with a faster reaction rate if the enzyme is not saturated.
A competitive inhibitor decreases the maximum rate at which a reaction can proceed.
When substrate is present in excess, the maximum reaction rate is unchanged in the presence of a competitive inhibitor.
Transcribed Image Text:The graph shows three plots of velocity (vo) versus substrate concentration ([S]). Determine which curve represents an enzyme's reaction velocity without any inhibitor present, which curve represents the velocity in the presence of a noncompetitive inhibitor, and which curve represents the velocity in the presence of a competitive inhibitor. max Vmax Vo Select all of the true statements. [S] (₂M) Answer Bank competitive inhibitor no inhibitor noncompetitive inhibitor A higher substrate concentration is associated with a faster reaction rate if the enzyme is not saturated. A competitive inhibitor decreases the maximum rate at which a reaction can proceed. When substrate is present in excess, the maximum reaction rate is unchanged in the presence of a competitive inhibitor.
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