The graph shows the velocity v(t) of an object. V(t) 4 3 2 1 5 V(t) 0 1 2 3 4 7 8 9 10 t Calculate the object's displacement between [1, 6]. O 12 O 12.5 O 13 O 13.5 6

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Velocity and Displacement Calculation from Graph

#### The graph shows the velocity v(t) of an object.

![Velocity Graph](image-url)

In the graph above:
- The x-axis represents time t.
- The y-axis represents the velocity v(t).
- The graph spans from t = 1 to t = 10.

The graph shows the following key points:
- From t = 1 to t = 2, the velocity increases linearly from 1 to 2 units.
- From t = 2 to t = 3, the velocity remains constant at 2 units.
- From t = 3 to t = 4, the velocity increases linearly from 2 to 3 units.
- From t = 4 to t = 6, the velocity remains constant at 3 units.
- From t = 6 to t = 7, the velocity decreases linearly from 3 to 2 units.
- From t = 7 to t = 8, the velocity remains constant at 2 units.
- From t = 8 to t = 9, the velocity decreases linearly from 2 to 1 unit.
- From t = 9 to t = 10, the velocity remains constant at 1 unit.

#### Calculation of Displacement
To calculate the displacement of the object between t = 1 and t = 6, we need to find the area under the velocity-time graph in this time interval.

**Area Calculation:**
- Area from t = 1 to t = 2 (Trapezoid): \( \frac{1}{2}(1+2) \times 1 = 1.5 \)
- Area from t = 2 to t = 3 (Rectangle): \( 2 \times 1 = 2 \)
- Area from t = 3 to t = 4 (Trapezoid): \( \frac{1}{2}(2+3) \times 1 = 2.5 \)
- Area from t = 4 to t = 6 (Rectangle): \( 3 \times 2 = 6 \)

**Total Displacement:**
Total displacement between t = 1 and t = 6 = \(1.5 + 2 + 2.5 + 6 = 12\) units

**Multiple Choice Answer:**
- \(\bigcirc\) 12
- \( \
Transcribed Image Text:### Velocity and Displacement Calculation from Graph #### The graph shows the velocity v(t) of an object. ![Velocity Graph](image-url) In the graph above: - The x-axis represents time t. - The y-axis represents the velocity v(t). - The graph spans from t = 1 to t = 10. The graph shows the following key points: - From t = 1 to t = 2, the velocity increases linearly from 1 to 2 units. - From t = 2 to t = 3, the velocity remains constant at 2 units. - From t = 3 to t = 4, the velocity increases linearly from 2 to 3 units. - From t = 4 to t = 6, the velocity remains constant at 3 units. - From t = 6 to t = 7, the velocity decreases linearly from 3 to 2 units. - From t = 7 to t = 8, the velocity remains constant at 2 units. - From t = 8 to t = 9, the velocity decreases linearly from 2 to 1 unit. - From t = 9 to t = 10, the velocity remains constant at 1 unit. #### Calculation of Displacement To calculate the displacement of the object between t = 1 and t = 6, we need to find the area under the velocity-time graph in this time interval. **Area Calculation:** - Area from t = 1 to t = 2 (Trapezoid): \( \frac{1}{2}(1+2) \times 1 = 1.5 \) - Area from t = 2 to t = 3 (Rectangle): \( 2 \times 1 = 2 \) - Area from t = 3 to t = 4 (Trapezoid): \( \frac{1}{2}(2+3) \times 1 = 2.5 \) - Area from t = 4 to t = 6 (Rectangle): \( 3 \times 2 = 6 \) **Total Displacement:** Total displacement between t = 1 and t = 6 = \(1.5 + 2 + 2.5 + 6 = 12\) units **Multiple Choice Answer:** - \(\bigcirc\) 12 - \( \
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