The graph shows the force on an object as a function of position. What is the work done on the object as it moves from 0 m to 6 m? Work done by variable force 15 10 5 1 3 4 5 Position (m) 15.5 J 72.5 J 90 J 75 J Force (N) 20
The graph shows the force on an object as a function of position. What is the work done on the object as it moves from 0 m to 6 m? Work done by variable force 15 10 5 1 3 4 5 Position (m) 15.5 J 72.5 J 90 J 75 J Force (N) 20
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:The image presents a physics problem involving a graph and multiple choice answers related to work done by a force on an object.
**Problem Statement:**
The graph shows the force on an object as a function of position. What is the work done on the object as it moves from 0 m to 6 m?
**Graph Description:**
- The graph is titled "Work done by variable force."
- The x-axis represents Position (m) ranging from 0 to 6.
- The y-axis represents Force (N) ranging from 5 to 20.
- The force increases linearly from 5 N to 15 N between 0 m and 2 m.
- The force remains constant at 15 N between 2 m and 5 m.
- The force decreases linearly back to 5 N from 5 m to 6 m.
**Options:**
- 15.5 J
- 72.5 J
- 90 J
- **75 J** (This option is selected)
- 15.0 J
This exercise requires calculating the work done by finding the area under the curve of the force-position graph from 0 m to 6 m. The correct answer, as indicated, is 75 J.
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